Organic Chemistry
6th Edition
ISBN: 9781936221349
Author: Marc Loudon, Jim Parise
Publisher: W. H. Freeman
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Chapter 20, Problem 20.39AP
Interpretation Introduction
Interpretation:
The way by which the configuration of the optically active hydrocarbon,
Concept introduction:
A carbon atom that has four nonequivalent atoms or groups attached to it is known as the chiral carbon atom. Chiral carbon centers are also called asymmetric or stereogenic centers. A chiral molecule is an optically active molecule. It rotates the plane of a plane polarized light.
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1, part A) We observe 6 carbon stereocenters in the molecule below. Indicate each stereocenter, and give the absolute S or R configuration.
1, part B) Indicate each stereoisomer in this molecule, and give the absolute S or R configuration. Then, indicate E or Z configuration of all alkenes in it (*ignoring aromatic ring*).
The following data was collected for this experiment:
A sample of 0.8281 g of phenylsuccinic acid was dissolved in 10 mL of acetone.
This sample gave a reading, aobs, of +10.278 deg on the polarimeter.
A tube measuring 1 dm was used for the sample.
What is the major enantiomer present in this sample?
Calculate the concentration of the sample used in g/mL.
Calculate the observed specific rotation [a]obs of the sample. Give your answer to 4 significant figures.
The NMR spectrum of bromocyclohexane indicates a low field signal (1H) at δ 4.16. To room temperature, this signal is a singlet, but at -75 ° C it separates into two peaks of unequal area (but totaling one proton): δ 3.97 and δ 4.64, in ratio 4.6: 1.0. How do you explain the doubling in two peaks? According to the generalization of the previous problem, what conformation of the molecule predominates (at -75 ° C)? What percentage of the molecules does it correspond to?
Solve all parts otherwise down vote and hand written solution
Chapter 20 Solutions
Organic Chemistry
Ch. 20 - Prob. 20.1PCh. 20 - Prob. 20.2PCh. 20 - Prob. 20.3PCh. 20 - Prob. 20.4PCh. 20 - Prob. 20.5PCh. 20 - Prob. 20.6PCh. 20 - Prob. 20.7PCh. 20 - Prob. 20.8PCh. 20 - Prob. 20.9PCh. 20 - Prob. 20.10P
Ch. 20 - Prob. 20.11PCh. 20 - Prob. 20.12PCh. 20 - Prob. 20.13PCh. 20 - Prob. 20.14PCh. 20 - Prob. 20.15PCh. 20 - Prob. 20.16PCh. 20 - Prob. 20.17PCh. 20 - Prob. 20.18PCh. 20 - Prob. 20.19PCh. 20 - Prob. 20.20PCh. 20 - Prob. 20.21PCh. 20 - Prob. 20.22PCh. 20 - Prob. 20.23PCh. 20 - Prob. 20.24PCh. 20 - Prob. 20.25PCh. 20 - Prob. 20.26PCh. 20 - Prob. 20.27APCh. 20 - Prob. 20.28APCh. 20 - Prob. 20.29APCh. 20 - Prob. 20.30APCh. 20 - Prob. 20.31APCh. 20 - Prob. 20.32APCh. 20 - Prob. 20.33APCh. 20 - Prob. 20.34APCh. 20 - Prob. 20.35APCh. 20 - Prob. 20.36APCh. 20 - Prob. 20.37APCh. 20 - Prob. 20.38APCh. 20 - Prob. 20.39APCh. 20 - Prob. 20.40APCh. 20 - Prob. 20.41APCh. 20 - Prob. 20.42APCh. 20 - Prob. 20.43APCh. 20 - Prob. 20.44APCh. 20 - Prob. 20.45APCh. 20 - Prob. 20.46APCh. 20 - Prob. 20.47APCh. 20 - Prob. 20.48APCh. 20 - Prob. 20.49APCh. 20 - Prob. 20.50APCh. 20 - Prob. 20.51APCh. 20 - Prob. 20.52APCh. 20 - Prob. 20.53APCh. 20 - Prob. 20.54APCh. 20 - Prob. 20.55APCh. 20 - Prob. 20.56APCh. 20 - Prob. 20.57APCh. 20 - Prob. 20.58APCh. 20 - Prob. 20.59APCh. 20 - Prob. 20.60AP
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