(a)
Interpretation:
The reaction of crystal violet with
Concept introduction:
When a significant portion of an electronic charge is transported from an electron donor species to an electron acceptor species, such an electronic transition is called charge-transfer transition.
(b)
Interpretation:
The effect of sodium dodecyl sulfate (SDS) on the rate of the bleaching reaction between crystal violet with
Concept introduction:
The molecules of fatty acid associate with each other and form a spherical cluster in aqueous solution. This spherical cluster is called micelle. The formation of micelle depends upon the structure of fatty acid.
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Organic Chemistry
- The existence of the NIH shift was established by determining the major product obtained from rearrangement of the following arene oxide, in which a hydrogen has been replaced by a deuterium. a. What would be the major product if the NIH shift occurs? b. What would be the major product if the carbocation forms phenol by losing H+ or D+, rather than by going through the NIH shift?arrow_forwardAre compounds a and b potential products of the reaction - why?arrow_forwardFor each of the following mixtures of reactants, give (i) a plausible chemical equation and (ii) structurefor the organometallic product, and (iii) general reason for the course of the reaction: (a)methyllithium and W(CO)6, (b) Co2(CO)8 and AlBr3.arrow_forward
- We saw that acid anhydrides react with alcohols, water, and amines. In which of these reactions can the tetrahedral intermediate eliminate the carboxylate ion even if it does not lose a proton before the elimination step? Explainarrow_forwardGiven the following reaction sequence: What are the reagents for reaction 3? A) NaNH2 excess followed by water B) sulfuric acid and heatarrow_forwardThe azo compound shown below has a λmax value of 410 nm. When treated with hydrogen in the presence of palladium on carbon, the λmax changes significantly. Suggest a reason for this observation and predict whether the λmax value increases or decreases.arrow_forward
- Propanal and propanone react in a similar way with acidified aqueous potassium cyanide, KCN. For this reaction to occur reasonably quickly, the pH of the solution should be approximately 4. The reaction of propanal proceeds with acidified potassium cyanide proceeds more rapidly than that of propanone. Referring to the mechanism of the reactions, explain this phenomenon.arrow_forwardA chemist needs an ether to use as a solvent for a reaction and wants to synthesize it in one step from two of the following available reagents: sodium ethoxide, bromomethane, potassium tert-butoxide, and 2-bromo-2-methylpropane. i) Which combination(s) will give a good yield of an ether? Illustrate, showing the mechanism of the reaction. ii) Illustrate with a mechanism the reaction of one of the combinations that will not yield an ether?arrow_forwardWhat is the catalyst in the reaction and which compound 5 or 6 is preferred?arrow_forward
- An ion with a positively charged nitrogen atom in a three-membered ring is called an aziridinium ion. The following aziridinium ion reacts with sodiummethoxide to form compounds A and B: If a small amount of aqueous Br2 is added to A, the reddish color of Br2 persists, but the color disappears when Br2 is added to B. When the aziridinium ion reacts with methanol, only A is formed. Identify A and B.arrow_forwardWrite a mechanism that accounts for the formation of ethyl isopropyl ether as one of the products in the following reaction. A. Write the mechanism for step one of this reaction. Show lone pairs and formal charges. Only the acidic hydrogen should be drawn out with a covalent bond. B. Write the mechanism for step two of this reaction (where the product of step one reacts with the solvent, ethanol). Show lone pairs and formal charges. Only the acidic hydrogen should be drawn out with a covalent bond. C.Write the mechanism for the last step of this reaction (formation of ethyl isopropyl ether). Show lone pairs and formal charges. Only the acidic hydrogen should be drawn out with a covalent bond. Cl- will act as the base in this reaction.arrow_forwardin the reaction, PrBr with NH3 gives a mixture of products. Why is an excess of NH3 required to give propylamine, PrNH2 as the major product?arrow_forward
- Organic ChemistryChemistryISBN:9781305580350Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. FootePublisher:Cengage Learning