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Answer to Problem 47E
The increasing order of the integral function is
Explanation of Solution
Given:
The graph of the function f is shown in Figure 1.
Calculation:
Plot the graph of the function f as shown below:
Refer the figure 1.
Consider the area under the graph are
The area
The area
The area
The area
The first smallest value among the integral is
The area denoted by
The second smallest area under the plot is
The value of
The value of
The third smallest area under the plot is
This is the difference of maximum positive area and maximum negative area.
The largest area under the plot is
The area denoted by
The second largest area under the plot is
Refer to the Figure 1.
Thus, the area denoted by
Show the area in the increasing order as follows:
Therefore, the increasing order of integral is
Chapter 5 Solutions
Single Variable Calculus: Concepts and Contexts, Enhanced Edition
- Calculus: Early TranscendentalsCalculusISBN:9781285741550Author:James StewartPublisher:Cengage LearningThomas' Calculus (14th Edition)CalculusISBN:9780134438986Author:Joel R. Hass, Christopher E. Heil, Maurice D. WeirPublisher:PEARSONCalculus: Early Transcendentals (3rd Edition)CalculusISBN:9780134763644Author:William L. Briggs, Lyle Cochran, Bernard Gillett, Eric SchulzPublisher:PEARSON
- Calculus: Early TranscendentalsCalculusISBN:9781319050740Author:Jon Rogawski, Colin Adams, Robert FranzosaPublisher:W. H. FreemanCalculus: Early Transcendental FunctionsCalculusISBN:9781337552516Author:Ron Larson, Bruce H. EdwardsPublisher:Cengage Learning