   Chapter 7, Problem 46AP

Chapter
Section
Textbook Problem

Additional ProblemsA synchronous satellite. which always remains above the same point on a planet's equator, is put in circular orbit around Jupiter to study that planet's famous red spot. Jupiter rotates once every 9.84 h. Use the data of Table 7.3 to find the altitude of the satellite.

To determine
The altitude of the satellite that put in circular orbit around Jupiter.

Explanation

Given info: The gravitational constant is 6.67×1011Nm2/kg2 , mass of Jupiter is 1.90×1027kg , and the period of Jupiter is 9.84h .

Explanation: From Kepler’s third law, the period of the satellite in an orbit around Jupiter is defined as T2=(4π2/GMJ)r3 and this expression can be rearranged to the radius r of the orbit from center of Jupiter.

The formula for the radius of the orbit of the satellite from center of Jupiter is,

r=(GMJT24π2)1/3

• G is gravitational constant.
• MJ is mass of Jupiter.
• T is period of Jupiter.

Substitute 6.67×1011Nm2/kg2 for G , 1.90×1027kg for MJ , and 9.84h for T to find r .

r=((6.67×1011Nm2/kg2)(1

Still sussing out bartleby?

Check out a sample textbook solution.

See a sample solution

The Solution to Your Study Problems

Bartleby provides explanations to thousands of textbook problems written by our experts, many with advanced degrees!

Get Started

Find more solutions based on key concepts 