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Chapter 8, Problem 21P
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### College Physics

11th Edition
Raymond A. Serway + 1 other
ISBN: 9781305952300

#### Solutions

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### College Physics

11th Edition
Raymond A. Serway + 1 other
ISBN: 9781305952300
Textbook Problem
To determine
The location of the center of gravity from the woman’s feet.

Explanation

The following figure shows the forces on the woman.

Given info: The scale reading are 380â€‰N and 320â€‰N respectively, weight of the woman is 700â€‰N , the force acts on her head is 380â€‰N , and the separation between the forces Fg1 and Fg2 is 2.00â€‰m .

Explanation: Assume that the weight of the plank was neglected and the condition for the equilibrium is used and it could be written as âˆ‘Fy=0=Fg1+Fg2âˆ’W . Consider the point where the force Fâ†’g2 acts as a pivot point and the condition of static torque on her about the point is defined as âˆ‘Ï„=0=xWâˆ’dFg1 .

The formula for the weight of the woman is,

W=Fg1+Fg2

• Fg1 is the left scale reading.
• Fg2 is the right scale reading.

Substitute 380â€‰N for Fg1 and 320â€‰N for Fg2 to find W

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