   Chapter 10.3, Problem 10.7CYU

Chapter
Section
Textbook Problem

At 1.00 atm and 25 °C, the density of dry air is 1.18 g/L. If the air is heated to 55 °C at constant pressure, what is its density?

Interpretation Introduction

Interpretation:

The density of air should be determined.  The density of air at 1atmand25°C is given and the air is heated to 55°C

Concept Introduction:

Density of a gas can be find out with the help of ideal gas equation which is

PV=nRT

n in the given equation can be written as mM since amount of any substance is given by dividing mass with molar mass.

PV=mMRTmV=PMRTdensity=PMRT

Explanation

We know that density=PMRT

Given:

densityofdryair=1.18g/molP=1atmT=25°C=298K

density=PMRTM=dRTP=1.18g/mol×0.08257L.atm/K.mol×298K1atm1atm=28

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