Chapter 10.3, Problem 10.7CYU

### Chemistry & Chemical Reactivity

10th Edition
John C. Kotz + 3 others
ISBN: 9781337399074

Chapter
Section

### Chemistry & Chemical Reactivity

10th Edition
John C. Kotz + 3 others
ISBN: 9781337399074
Textbook Problem

# At 1.00 atm and 25 °C, the density of dry air is 1.18 g/L. If the air is heated to 55 °C at constant pressure, what is its density?

Interpretation Introduction

Interpretation:

The density of air should be determined.  The density of air at 1atmand25°C is given and the air is heated to 55°C

Concept Introduction:

Density of a gas can be find out with the help of ideal gas equation which is

PV=nRT

n in the given equation can be written as mM since amount of any substance is given by dividing mass with molar mass.

PV=mMRTmV=PMRTdensity=PMRT

Explanation

We know that densityâ€‰=â€‰PMRT

Given:

â€‚Â densityâ€‰ofâ€‰dryâ€‰airâ€‰â€‰=â€‰â€‰1.18â€‰g/molPâ€‰â€‰â€‰â€‰â€‰â€‰â€‰â€‰â€‰â€‰â€‰â€‰â€‰=â€‰â€‰â€‰â€‰â€‰1â€‰atmTâ€‰â€‰â€‰â€‰â€‰â€‰â€‰â€‰â€‰â€‰â€‰â€‰â€‰=25Â°Câ€‰â€‰â€‰=â€‰â€‰â€‰298K

â€‚Â densityâ€‰=â€‰PMRTMâ€‰â€‰â€‰â€‰â€‰â€‰â€‰â€‰â€‰=â€‰â€‰dRTPâ€‰â€‰â€‰â€‰â€‰â€‰â€‰â€‰â€‰â€‰â€‰â€‰â€‰â€‰â€‰â€‰=â€‰1.18â€‰g/molâ€‰Ã—0.08257â€‰L.atm/K.molâ€‰Ã—â€‰298K1â€‰atmâ€‰1â€‰atmâ€‰â€‰â€‰â€‰â€‰â€‰â€‰â€‰â€‰â€‰â€‰â€‰â€‰â€‰â€‰â€‰â€‰=â€‰28

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