   Chapter 11, Problem 13P

Chapter
Section
Textbook Problem

A 0.200-kg aluminum cup contains 800. g of water in thermal equilibrium with the cup at 80.°C. The combination of cup and water is cooled uniformly so that the temperature decreases by 1.5°C per minute. At what rate is energy being removed? Express your answer in watts.

To determine
Rate at which the energy is being removed.

Explanation

Given Info: Mass of the aluminum cup is 0.200 kg, mass of the water is 800 kg, rate of decrease in temperature is 15°C/min .

Formula to the rate of energy transfer is,

P=QΔt

• P is the rate of energy transfer,
• Q is the heat energy given out from water – cup system.
• Δt is the time,

Formula to calculate the heat energy of the water – cup system is,

Q=[mWcW+mCupcCup]ΔT

• mW is the mass of water,
• mCup is the mass of the cup,
• cW is the specific heat of water,
• cCup is the specific heat of cup,
• ΔT is the change in temperature,

Use [mWcW+mCupcCup]ΔT for Q in P=QΔt .

P=[mWcW+mCupcCup]ΔTΔt=[mWcW+mCupcCup](ΔTΔt)

Substitute 0

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