   Chapter 11, Problem 14P

Chapter
Section
Textbook Problem

A 1.5-kg copper block is given an initial speed of 3.0 m/s on a rough horizontal surface. Because of friction, the block finally comes to rest. (a) If the block absorbs 85% of its initial kinetic energy as internal energy, calculate its increase in temperature. (b) What happens to the remaining energy?

(a)

To determine
Calculate increase in temperature.

Explanation

Given Info: Block absorbs 85% if kinetic energy as internal energy, mass of the block of the 1.5 kg, and initial speed is 3.0m/s .

Formula to calculate the kinetic energy is,

KE=12mv2

• KE is the kinetic energy of the block,
• m is the mass of the block,
• v is the velocity of the block,

Formula to calculate the energy required to raise the temperature of the block,

Q=mcΔT

• Q is the energy required to raise the internal temperature of the coin,
• c is the specific heat of copper,
• ΔT is the change in temperature of the block,

Block absorbs 85% if kinetic energy as internal energy. So,

Formula to calculate the internal energy of the block is,

Q=85%(KE)

Use 85%(1/2mv2) for KE  and mcΔT for Q in the above equation.

85%(12mv2)=mcΔT85100(12mv2)=mcΔTΔT=0

(b)

To determine
Whether the result depends upon the mass of the coin.

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