   Chapter 13, Problem 142AP ### Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425

#### Solutions

Chapter
Section ### Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425
Textbook Problem
17 views

# hen sodium bicarbonate, NaHCO 3 ( s ) , is heated, sodium carbonate is produced, with the evolution of water vapor and carbon dioxide gas.msp;  2NaHCO 3 ( s )   Na2CO 3 ( s ) + H 2 O ( g ) + CO 2 ( g ) at total volume of gas, measured at 29  ° C and 769 torr, is produced when 1 .00  g of NaHCO 3 ( s ) is completely converted to Na 2 CO 3 ( s ) ?

Interpretation Introduction

Interpretation:

To determine the total volume of gas evolved during complete conversion of NaHCO3 to Na2 CO3.

Concept Introduction:

Mole concept must be used to determine the moles of products formed during the reaction. Then moles of gases give the information about volume of gases evolved at certain temperature and pressure.

Explanation

Given information:

The balance chemical reaction of conversion of NaHCO3 to Na2 CO3.

2NaHCO3(s)Na2CO3(s)+H2O(g)+CO2(g)

Temperature = 29°C

Pressure = 769 torr

Mass of NaHCO3 = 1.00 g.

The balance equation gives idea about mole ratio of reactant and products. Hence, the mole ratio of NaHCO3 with H2 O and CO2 is 2:1. So, the moles of both products can be calculated that is 0.0059 moles.

Molar mass of NaHCO3 = 84.0 g/mol.

Hence, number of moles of NaHCO3 = massmolar mass=1.00 g84.0 g/mol=0.012 moles

According to given balance equation, 2 moles of NaHCO3 form 1 mole of H2 O gas. Therefore,

0.012mol of NaHCO3×1mol of H2O2 mol of NaHCO3=0.006 mol of H2O gas

According to given balance equation, 2 moles of NaHCO3 form 1 mole of CO2 gas

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