General, Organic, and Biological Chemistry - 4th edition
4th Edition
ISBN: 9781259883989
Author: by Janice Smith
Publisher: McGraw-Hill Education
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Question
Chapter 15.3, Problem 15.7P
Interpretation Introduction
Interpretation:
The following ball-and-stick model should be translated to shorthand structure and two chiral centers should be located for the same:
Concept Introduction:
Compounds containing four different groups attached to them are known as chiral compound and that carbon is known as chiral carbon. The chiral carbon in the given compound is represented by placing an asterisk (*) symbol over that carbon atom.
Blood clot formation in the human body is due synthesis of a special protein Vitamin K. This vitamin is also responsible for binding and controlling of calcium in bones and other tissues.
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Chapter 15 Solutions
General, Organic, and Biological Chemistry - 4th edition
Ch. 15.1 - Prob. 15.1PCh. 15.1 - Prob. 15.1PPCh. 15.1 - For trans-2-hexene: (a) draw a stereoisomer; (b)...Ch. 15.2 - Prob. 15.3PCh. 15.2 - Prob. 15.4PCh. 15.3 - Prob. 15.2PPCh. 15.3 - Prob. 15.5PCh. 15.3 - Prob. 15.6PCh. 15.3 - Prob. 15.3PPCh. 15.3 - Prob. 15.7P
Ch. 15.3 - Prob. 15.8PCh. 15.3 - Prob. 15.9PCh. 15.4 - Prob. 15.4PPCh. 15.4 - Prob. 15.10PCh. 15.4 - Prob. 15.11PCh. 15.4 - Prob. 15.12PCh. 15.5 - Prob. 15.13PCh. 15.6 - Prob. 15.5PPCh. 15.6 - Prob. 15.14PCh. 15.6 - Prob. 15.15PCh. 15.7 - Prob. 15.16PCh. 15.7 - Prob. 15.17PCh. 15.7 - Prob. 15.6PPCh. 15.7 - Prob. 15.18PCh. 15.8 - Prob. 15.7PPCh. 15.8 - Prob. 15.19PCh. 15.9 - Prob. 15.20PCh. 15 - Prob. 21PCh. 15 - Prob. 22PCh. 15 - Prob. 23PCh. 15 - Prob. 24PCh. 15 - Prob. 25PCh. 15 - Prob. 26PCh. 15 - Prob. 27PCh. 15 - Prob. 28PCh. 15 - Prob. 29PCh. 15 - Prob. 30PCh. 15 - Prob. 31PCh. 15 - Prob. 32PCh. 15 - Prob. 33PCh. 15 - Prob. 34PCh. 15 - Prob. 35PCh. 15 - Prob. 36PCh. 15 - How are the compounds in each pair related? Are...Ch. 15 - Prob. 38PCh. 15 - Prob. 39PCh. 15 - Prob. 40PCh. 15 - Prob. 41PCh. 15 - Prob. 42PCh. 15 - Prob. 43PCh. 15 - Prob. 44PCh. 15 - Prob. 45PCh. 15 - Prob. 46PCh. 15 - Prob. 47PCh. 15 - Prob. 48PCh. 15 - Prob. 49PCh. 15 - Prob. 50PCh. 15 - (a) Define the terms “optically active” and...Ch. 15 - Prob. 52PCh. 15 - Prob. 53PCh. 15 - Prob. 54PCh. 15 - Prob. 55PCh. 15 - Prob. 56PCh. 15 - Prob. 57PCh. 15 - Prob. 58PCh. 15 - Prob. 59PCh. 15 - Prob. 60PCh. 15 - Prob. 61PCh. 15 - Prob. 62PCh. 15 - Prob. 63PCh. 15 - Prob. 64PCh. 15 - Prob. 65PCh. 15 - Prob. 66PCh. 15 - Prob. 67CPCh. 15 - Prob. 68CP
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- Draw and identify (R) and (S) enantiomers of lactic acid, CH3CH(OH)COOH. Use the proper conventions to draw Fischer projections.arrow_forwardWhat are I and II? A.) constitutional isomers B.) Enantiomers C.) Diastereomers D.) Identicalarrow_forwardA(n) ________ is an achiral compound that contains chiral centers but is superimposable on its mirror image. A) constitutional isomers B) conformational isomers C) enantiomers D) diastereomers E) meso compoundsarrow_forward
- What is the configuration at the chiral centers of the Fischer projection of the molecule shown? (The molecule is drawn with C1 at the top and C5 at the bottom.)arrow_forwardExplain the difference between an enantiomer and an epimer. a. Enantiomers are non-superimposable mirror image structures. Epimers are diastereomers that differ only in the orientation of one chiral center. b. Epimers are non-superimposable mirror image structures. Enantiomers are diastereomers that differ only in the orientation of one chiral center.arrow_forwardIdentify the chirality centersarrow_forward
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