Consider the following half-reactions: Explain why platinum metal will dissolve in aqua regia (a mixture of hydrochloric and nitric acids) but not in either concentrated nitric or concentrated hydrochloric acid individually.

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Interpretation Introduction Interpretation: The half cell reaction for the reaction of Platinum with Hydrochloric acid and Nitric acid is given. The dissolution of Platinum in aqua regia, but not in Hydrochloric acid or Nitric acid is to be explained Concept introduction: Aqua regia consists of Hydrochloric acid and Nitric acid in the ratio of 1 : 3 . The reaction of Platinum with aqua regia produces Chloroplatinuous acid and Nitrosoplatinic chloride To determine: The process by which attachment of Zinc to the hull would protect the Monitor from further corrosion. Explanation Given, The reduction potential values are given as, Pt 2 + + 2 e − → Pt E ° = 1.188 V PtCl 4 2 − + 2 e − → Pt + 4 Cl − E ° = 0.755 V NO 3 − + 4 H + + 3 e − → NO + 2 H 2 O E ° = 0.96 V When the reactions are written in the form of their oxidation potential, Pt → Pt 2 + + 2 e − E ° = − 1

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Answer 1

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Chemistry: An Atoms First Approach

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Steven S. Zumdahl + 1 other

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BuyFind

Chemistry: An Atoms First Approach

2nd Edition

Steven S. Zumdahl + 1 other

Publisher: Cengage Learning

ISBN: 9781305079243

Solutions

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Section

Answer 3

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Section

Answer 4

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Answer 5

Interpretation Introduction

Interpretation:

The half cell reaction for the reaction of Platinum with Hydrochloric acid and Nitric acid is given. The dissolution of Platinum in aqua regia, but not in Hydrochloric acid or Nitric acid is to be explained

Concept introduction:

Aqua regia consists of Hydrochloric acid and Nitric acid in the ratio of 1:3 . The reaction of Platinum with aqua regia produces Chloroplatinuous acid and Nitrosoplatinic chloride

To determine: The process by which attachment of Zinc to the hull would protect the Monitor from further corrosion.

Explanation of Solution

Given,

The reduction potential values are given as,

Pt2++2e−→Pt E°=1.188 VPtCl42−+2e−→Pt+4Cl− E°=0.755 VNO3−+4H++3e−→NO+2H2O E°=0.96 V

When the reactions are written in the form of their oxidation potential,

Pt→Pt2++2e− E°=−1

Consider the following half-reactions: Explain why platinum metal will dissolve in aqua regia (a mixture of hydrochloric and nitric acids) but not in either concentrated nitric or concentrated hydrochloric acid individually.

Chemistry: An Atoms First Approach

Solutions

Chemistry: An Atoms First Approach

Consider the following half-reactions:

Explain why platinum metal will dissolve in aqua regia (a mixture of hydrochloric and nitric acids) but not in either concentrated nitric or concentrated hydrochloric acid individually.

Explanation of Solution

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