   Chapter 17, Problem 89AP ### Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425

#### Solutions

Chapter
Section ### Introductory Chemistry: A Foundati...

9th Edition
Steven S. Zumdahl + 1 other
ISBN: 9781337399425
Textbook Problem
6 views

# . For the reaction CaCO 3 ( s ) ⇌ CaO ( s ) + CO 2 ( g )    the equilibrium constant K has the form K = [ CO 2 ] . Using a handbook to find density information about CaCO3(s) and CaO(s), show that the concentrations of the two solids (the number of moles contained in 1 L of volume) are constant.

Interpretation Introduction

Interpretation:

Using a handbook to find density information about CaCO3(s) and CaO(s), it is to be shown that the concentrations of the two solids are constant.

Concept Introduction:

The density of a substance is defined as the ratio of the mass and the volume of a substance. The higher molar mass of a substance corresponds to a higher density value.

The concentration of a solution is defined as the number of moles of solute dissolved in a liter of solution. Concentration of a solution is expressed in moles per unit volume of a substance.

Explanation

The given chemical reaction is,

CaCO3(s)CaO(s)+CO2(g)

According to the law of chemical equilibrium, the equilibrium expression for the above reaction is,

K=[CO2]

The density of calcium carbonate is 2.71 g/cm3.

The density of calcium oxide is 3.35 g/cm3.

Calcium carbonate and calcium oxide both are in solid form. Therefore, they have a constant volume. The volume of both the compounds is assumed to be 100 cm3.

The amount of calcium carbonate is calculated by the formula,

Density=MassVolume

Substitute the values of density and volume of calcium carbonate in the above formula to calculate its mass.

2.71 g/cm3=Mass100 cm3Mass=2

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