   # Potassium perchlorate is prepared by the following sequence of reactions: Cl 2 (g) + 2 KOH(aq) → KCI(aq) + KCIO(aq) + H 2 O(l) 3 KCIO(aq) → 2 KCI(aq) + KCIO 3 (aq) 4 KCIO3(aq) → 3 KCIO 4 (aq) + KCI(aq) What mass of Cl 2 (g) is required to produce 234 kg of KClO 4 ? ### Chemistry & Chemical Reactivity

9th Edition
John C. Kotz + 3 others
Publisher: Cengage Learning
ISBN: 9781133949640

#### Solutions

Chapter
Section ### Chemistry & Chemical Reactivity

9th Edition
John C. Kotz + 3 others
Publisher: Cengage Learning
ISBN: 9781133949640
Chapter 4, Problem 97GQ
Textbook Problem
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## Potassium perchlorate is prepared by the following sequence of reactions:Cl2(g) + 2 KOH(aq) → KCI(aq) + KCIO(aq) + H2O(l)3 KCIO(aq) → 2 KCI(aq) + KCIO3(aq)4 KCIO3(aq) → 3 KCIO4(aq) + KCI(aq)What mass of Cl2(g) is required to produce 234 kg of KClO4?

Interpretation Introduction

Interpretation:

The mass of Cl2 required to produce 234kg of KClO4 has to be determined.

Concept introduction:

Numberofmole=GivenmassofthesubstanceMolarmass

• Massofthesubstance=Amountofthesubstance×Molarmass
• The molar mass of an element or compound is the mass in grams of 1 mole of that substance, and it is expressed in the unit of grams per mol (g/mol).
• For chemical reaction balanced chemical reaction equation written in accordance with the Law of conservation of mass.
• Law of conservation of mass states that for a reaction total mass of the reactant and product must be equal.
• Stoichiometric factor is a relationship between reactant and product which is obtained from the balanced chemical equation for a particular reaction.

### Explanation of Solution

The balanced chemical equation for the sequence of reactions for the preparation of KClO4 are,

Cl2(g)+2KOH(aq)KCl(aq)+KClO(aq)+H2O(l) 3KClO(aq)2KCl(aq)+KClO3(aq) 4KClO3(aq)3KClO4(aq)+KCl(aq)

The amount (in moles) of KClO4 can be calculated by using the equation

No.ofmole = GivenmassofthesubstanceMolarmassNo

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