BuyFindarrow_forward

Chemistry

10th Edition
Steven S. Zumdahl + 2 others
ISBN: 9781305957404

Solutions

Chapter
Section
BuyFindarrow_forward

Chemistry

10th Edition
Steven S. Zumdahl + 2 others
ISBN: 9781305957404
Textbook Problem

What quantity of energy does it take to convert 0.500 kg ice at –20.°C to steam at 250.°C? Specific heat capacities: ice, 2.03 J/g • °C; liquid, 4.2 J/g . °C; steam, 2.0 J/g • °C; Hvap = 40.7 kJ/mol; Hfus = 6.02 kJ/mol.

Interpretation Introduction

Interpretation: The required amount of heat for water at -20°C to 250°C should be calculated.

Concept Introduction:

The heat capacity C is defined as the ratio of heat absorbed to the temperature change. It can be given by,

                                           C = Heat absorbedTemperature change

Require heat for an one gram of substance raise to its temperature by one degree Celsius is called specific heat capacity.

Specific heat capacity =  Absorbed heat (J)/ Temperature change(c)×mass ofsubstance (g)......(1)

For the above equation heat is:

                                                     q = S×M×ΔT......(2)

                                                       q is heat J

                                                       M is mass of sample (g)

                                                       S is specific heat capacity (J/°C·g)

                                                        ΔT  is temperature change (°C)

Explanation

Explanation

Record the given data:

                 Specific heat capacity of ice =   2.03 J/C.g

                 Specific heat capacity of steam = 2.0 J/C.g

                 Specific heat capacity of water 4.184 J/C.g

                 The  ΔΗvap =40.7 kJ/mol

                 The ΔΗfus = 6.02 kJ/mol

  • The given specific heat capacities, ΔΗvap and ΔΗfus are recorded as shown above.

To calculate the required heat of ice -20°C to 0°C .

The reaction is,

                              H2O(s-20°C)H2O(s0°C)

                          q1=2.30Jg.°C×5.00×102×20°C=2.0×104J=20kJ

  • The specific heat capacity of ice, temperature change and mass of ice are plugging in to equation 2 to give heat of ice -20°C to 0°C .
  • The heat of ice -20°C to 0°C is 20kJ .

To calculate the required heat of ice 0°C to water at 0°C .

The reaction is,

                              H2O(sol0°C)H2O(lq0°C)

Molecular weight of water is 18.02g

                          q2=×5.00×102×1mol18.02g×6.02kJmol=167kJ

  • The enthalpy of fusion and molecular weight of water are plugging in to equation  to give heat of ice 0°C to water at 0°C .
  • The heat ice 0°C to water at 0°C is 167kJ .

To calculate the required heat of water at 0°C in to 100°C .

The reaction is,

                              H2O(lq0°C)H2O(1q100°C)

                          q3=4.2Jg.°C×5.00×102×100°C=2

Still sussing out bartleby?

Check out a sample textbook solution.

See a sample solution

The Solution to Your Study Problems

Bartleby provides explanations to thousands of textbook problems written by our experts, many with advanced degrees!

Get Started

Chapter 10 Solutions

Show all chapter solutions add
Ch-10 P-1ALQCh-10 P-2ALQCh-10 P-3ALQCh-10 P-4ALQCh-10 P-5ALQCh-10 P-6ALQCh-10 P-7ALQCh-10 P-8ALQCh-10 P-9ALQCh-10 P-10ALQCh-10 P-11ALQCh-10 P-12ALQCh-10 P-13ALQCh-10 P-15QCh-10 P-16QCh-10 P-17QCh-10 P-18QCh-10 P-19QCh-10 P-20QCh-10 P-21QCh-10 P-22QCh-10 P-23QCh-10 P-24QCh-10 P-25QCh-10 P-26QCh-10 P-27QCh-10 P-29QCh-10 P-30QCh-10 P-31QCh-10 P-32QCh-10 P-34QCh-10 P-35QCh-10 P-36QCh-10 P-37ECh-10 P-38ECh-10 P-39ECh-10 P-40ECh-10 P-41ECh-10 P-42ECh-10 P-43ECh-10 P-44ECh-10 P-45ECh-10 P-46ECh-10 P-47ECh-10 P-48ECh-10 P-49ECh-10 P-50ECh-10 P-51ECh-10 P-52ECh-10 P-53ECh-10 P-54ECh-10 P-55ECh-10 P-56ECh-10 P-57ECh-10 P-58ECh-10 P-59ECh-10 P-60ECh-10 P-61ECh-10 P-62ECh-10 P-63ECh-10 P-64ECh-10 P-65ECh-10 P-66ECh-10 P-67ECh-10 P-68ECh-10 P-69ECh-10 P-70ECh-10 P-71ECh-10 P-72ECh-10 P-73ECh-10 P-74ECh-10 P-75ECh-10 P-76ECh-10 P-77ECh-10 P-78ECh-10 P-79ECh-10 P-80ECh-10 P-81ECh-10 P-82ECh-10 P-83ECh-10 P-84ECh-10 P-85ECh-10 P-86ECh-10 P-87ECh-10 P-88ECh-10 P-89ECh-10 P-90ECh-10 P-91ECh-10 P-92ECh-10 P-93ECh-10 P-94ECh-10 P-95ECh-10 P-96ECh-10 P-97ECh-10 P-98ECh-10 P-99ECh-10 P-100ECh-10 P-101ECh-10 P-103ECh-10 P-104ECh-10 P-105ECh-10 P-106ECh-10 P-107ECh-10 P-108ECh-10 P-109ECh-10 P-110ECh-10 P-111AECh-10 P-112AECh-10 P-113AECh-10 P-114AECh-10 P-115AECh-10 P-116AECh-10 P-117AECh-10 P-118AECh-10 P-119AECh-10 P-120AECh-10 P-121AECh-10 P-122AECh-10 P-123AECh-10 P-124AECh-10 P-125AECh-10 P-126AECh-10 P-127AECh-10 P-128AECh-10 P-129AECh-10 P-131CWPCh-10 P-132CWPCh-10 P-133CWPCh-10 P-134CWPCh-10 P-135CWPCh-10 P-136CWPCh-10 P-137CWPCh-10 P-138CWPCh-10 P-139CWPCh-10 P-140CWPCh-10 P-141CPCh-10 P-142CPCh-10 P-143CPCh-10 P-144CPCh-10 P-145CPCh-10 P-146CPCh-10 P-147CPCh-10 P-148CPCh-10 P-149CPCh-10 P-150CPCh-10 P-151CPCh-10 P-152CPCh-10 P-153CPCh-10 P-154CPCh-10 P-155CPCh-10 P-156CPCh-10 P-157IPCh-10 P-158IPCh-10 P-159IPCh-10 P-160MP

Additional Science Solutions

Find more solutions based on key concepts

Show solutions add

Behavior change is a process that takes place in stages. T F

Nutrition: Concepts and Controversies - Standalone book (MindTap Course List)

Match each substance with its correct description

Human Biology (MindTap Course List)

What characteristic do starts in a constellation or asterism share?

Horizons: Exploring the Universe (MindTap Course List)

In what way has biotechnology had an impact on agriculture in the United States?

Human Heredity: Principles and Issues (MindTap Course List)

Why is it safe for us to consume foods like vinegar that contain acetic acids?

Chemistry for Today: General, Organic, and Biochemistry

Characterize phenols in terms of their solubility in water.

General, Organic, and Biological Chemistry

A cubical gaussian surface is bisected by a large sheet of charge, parallel to its top and bottom faces. No oth...

Physics for Scientists and Engineers, Technology Update (No access codes included)