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Chemistry

10th Edition
Steven S. Zumdahl + 2 others
ISBN: 9781305957404

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BuyFindarrow_forward

Chemistry

10th Edition
Steven S. Zumdahl + 2 others
ISBN: 9781305957404
Textbook Problem

The melting point of a fictional substance X is 225°C at 10.0 atm. If the density of the solid phase of X is 2.67 g/cm3 and the density of the liquid phase is 2.78 g/cm3 at 10.0 atm, predict whether the normal melting point of X will be less than, equal to, or greater than 225°C. Explain.

Interpretation Introduction

Interpretation: Whetherthe normal melting point of substance X would be less than or greater than or equal to 225°C to be explained.

Concept introduction

Freezing point: Freezing point is defined as the temperature at which liquid into solid.

Boiling point: Boiling point is temperature at which the liquid into gas.

Elevation of boiling point: Elevation of boiling point of a liquid is occurrence that boiling point of a liquid would be greater when another substance is added to it. Resulting, the boiling point becomes higher than the pure solvent.

Depression of freezing point: Depression of freezing point is reducing in freezing point of a solvent when added non volatile solute. Volatile substance means easily vaporized at room temperature and non volatile means does not easily evaporate at room temperature.

Explanation

Explanation

Record the given data

Melting point of a substance X = 225°C at 10.0 atm

Density of solid phase of X = 2.67g/cm3

Density of liquid phase of X = 2.78g/cm3at10.0 atm

Melting point, density of solid phase and liquid phase of X are recorded as shown

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