   Chapter 10, Problem 144CP

Chapter
Section
Textbook Problem

Consider a perfectly insulated and sealed container. Determine the minimum volume of a container such that a gallon of water at 25°C will evaporate completely. If the container is a cube, determine the dimensions in feet. Assume the density of water is 0.998 g/cm3.

Interpretation Introduction

Interpretation: The minimum volume and dimensions in feet of a container and should be calculated.

Concept Introduction:

Charles’s law:

At constant pressure (P), for a given mass of gas, the volume (V) is directly proportional to the absolute temperature (T). The expression for Charles’s law is given by,

V=(nRP)T......(1)

Where (nRP)=constant

Explanation

Explanation

Record the given data:

Volume of water is 1gal.

Density of water is 0.998 g/cm3

The temperature of water is 25°C .

• The given volume and density of water at 25°C are recorded as shown above.

To convert the moles of water in given 1gal volume.

Molecular weight of water is 18.02g

=1gal×3785mLgal×0.998gmL×1molwater18.02g=210molwater

• The given density and volume of water are plugging in above equation to give the mole of water in given 1gal volume.
• mole of water in given 1gal is 210mol .

To calculate the minimum volume and dimensions in feet of a container.

Molecular weight of water is 18.02g

Vapor pressure of H2O at 25°C is 23.756 torr

=210mol×0.08206L.atmKmol23

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