Chapter 14, Problem 40A

Interpretation Introduction

Interpretation:

The intermolecular forces that exist in a sample of solid krypton, Kr, with those that exist in a diamond, C have to be compared.

Concept Introduction:

Crystalline solids are solid compounds with the highly ordered structure of the constituents (atoms, molecules or ions). Depending on the constituents (atoms, molecules or ions), the crystalline solids are classified into three types-

1. Ionic solids
2. Molecular solids
3. Atomic solids

Explanation of Solution

Diamond is an atomic solid, the particles in a diamond are held together through strong covalent bonding. In diamond, each carbon is attached to four other carbons through C-C covalent bonds which make diamond the hardest solid.Solid Kr is a molecular solid and the particles in solid Kr are held together by weaker London dispersion forces.