Chapter 15, Problem 9PS

### Chemistry & Chemical Reactivity

10th Edition
John C. Kotz + 3 others
ISBN: 9781337399074

Chapter
Section

### Chemistry & Chemical Reactivity

10th Edition
John C. Kotz + 3 others
ISBN: 9781337399074
Textbook Problem

# The reactionC(s) + CO2(g) ⇄ 2 CO(g)occurs at high temperatures. At 700 °C, a 200.0-L tank contains 1.0 mol of CO, 0.20 mol of CO2, and 0.40 mol of C at equilibrium. (a) Calculate Kc for the reaction at 700 °C. (b) Calculate Kc for the reaction, also at 700 °C, if the amounts at equilibrium in the 200.0-L tank are 1.0 mol of CO, 0.20 mol of CO2, and 0.80 mol of C. (c) Compare the results of (a) and (b). Does the quantity of carbon affect the value of Kc? Explain.

(a)

Interpretation Introduction

Interpretation: The equilibrium constant Kc for the reaction in the given conditions has to be calculated and the quantity of carbon affecting the value of Kc has to be explained.

Concept introduction:

• Equilibrium constant: At equilibrium the ratio of products to reactants has a constant value. And it is represented by the letter K.

For a general reaction, aA+bBcC+dD

The equilibrium constant Kc= [C]c[D]d[A]a[B]b, where a, b, c and d are the stoichiometric coefficients of reactant and product in the reaction. Concentration value for solid substance is 1.

• Concentration =AmountofsubstanceVolume
Explanation

The balanced chemical equation for the given reaction is,

C(s)â€‰+â€‰CO2(g)â‡„â€‰â€‰2CO(g)

By using the given amount of reactants and product, their concentration can be calculated by using the equation,

ConcentrationÂ =â€‰â€‰Amountâ€‰â€‰ofâ€‰â€‰substanceVolume

Concentration of CO2â€‰= 0.20â€‰â€‰mol200â€‰Lâ€‰â€‰=â€‰â€‰1Ã—10âˆ’3â€‰â€‰mol/L

Concentration of â€‰COÂ  = 1â€‰

(b)

Interpretation Introduction

Interpretation: The equilibrium constant Kc for the reaction in the given conditions has to be calculated and the quantity of carbon affecting the value of Kc has to be explained.

Concept introduction:

• Equilibrium constant: At equilibrium the ratio of products to reactants has a constant value. And it is represented by the letter K.

For a general reaction, aA+bBcC+dD

The equilibrium constant Kc= [C]c[D]d[A]a[B]b, where a, b, c and d are the stoichiometric coefficients of reactant and product in the reaction. Concentration value for solid substance is 1.

• Concentration =AmountofsubstanceVolume

(c)

Interpretation Introduction

Interpretation: The equilibrium constant Kc for the reaction in the given conditions has to be calculated and the quantity of carbon affecting the value of Kc has to be explained.

Concept introduction:

• Equilibrium constant: At equilibrium the ratio of products to reactants has a constant value. And it is represented by the letter K.

For a general reaction, aA+bBcC+dD

The equilibrium constant Kc= [C]c[D]d[A]a[B]b, where a, b, c and d are the stoichiometric coefficients of reactant and product in the reaction. Concentration value for solid substance is 1.

• Concentration =AmountofsubstanceVolume

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