Biochemistry: The Molecular Basis of Life
6th Edition
ISBN: 9780190209896
Author: Trudy McKee, James R. McKee
Publisher: Oxford University Press
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Chapter 16, Problem 10RQ
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Which of the following methods has the highest sensitivity, specificity, and accuracy as far asdetecting DNA mutations in clinical applications?A. ELISAB. High-density oligonucleotide arrayC. PCR-RFLPD. Single-strand conformation polymorphism
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The following assay based on the enzyme protein kinase A (PKA) can be used to measure cAMP level in cell. PKA is an oligomeric protein consisted of two regulatory (R) and two catalytic (C) subunits. The R2C2 complex is catalytically inactive. The binding of cAMP to the R subunits results in a conformational change such that the R subunits are released from the complex. The free catalytic (C) subunits are then enzymatically active. In the cAMP assay, the gene of the R subunit is fused with that of GFP (excitation: 465 nm, emission 545 nm) while the gene of the C subunit is fused with that of BFP (excitation: 380 nm, emission: 465 nm). These two hybrid fluorescent proteins are then expressed in the cell. Explain how such a system can be exploited to follow the concentration of cAMP in cell.
Chapter 16 Solutions
Biochemistry: The Molecular Basis of Life
Chapter 16, Problem 1QChapter 16, Problem 2QChapter 16, Problem 3QChapter 16, Problem 4QChapter 16, Problem 5QChapter 16, Problem 6QChapter 16, Problem 7QChapter 16, Problem 8QChapter 16, Problem 1RQChapter 16, Problem 2RQ
Chapter 16, Problem 3RQChapter 16, Problem 4RQChapter 16, Problem 5RQChapter 16, Problem 6RQChapter 16, Problem 7RQChapter 16, Problem 8RQChapter 16, Problem 9RQChapter 16, Problem 10RQChapter 16, Problem 11RQChapter 16, Problem 12RQChapter 16, Problem 13RQChapter 16, Problem 14RQChapter 16, Problem 15RQChapter 16, Problem 16RQChapter 16, Problem 17RQChapter 16, Problem 18RQChapter 16, Problem 19RQChapter 16, Problem 20RQChapter 16, Problem 21RQChapter 16, Problem 22RQChapter 16, Problem 23RQChapter 16, Problem 24RQChapter 16, Problem 25RQChapter 16, Problem 26RQChapter 16, Problem 27RQChapter 16, Problem 28RQChapter 16, Problem 29RQChapter 16, Problem 30RQChapter 16, Problem 31RQChapter 16, Problem 32RQChapter 16, Problem 33RQChapter 16, Problem 34FBChapter 16, Problem 35FBChapter 16, Problem 36FBChapter 16, Problem 37FBChapter 16, Problem 38FBChapter 16, Problem 39FBChapter 16, Problem 40FBChapter 16, Problem 41FBChapter 16, Problem 42FBChapter 16, Problem 43FBChapter 16, Problem 44SAChapter 16, Problem 45SAChapter 16, Problem 46SAChapter 16, Problem 47SAChapter 16, Problem 48SAChapter 16, Problem 49TQChapter 16, Problem 50TQChapter 16, Problem 51TQChapter 16, Problem 52TQChapter 16, Problem 53TQChapter 16, Problem 54TQChapter 16, Problem 55TQChapter 16, Problem 56TQChapter 16, Problem 57TQChapter 16, Problem 58TQChapter 16, Problem 59TQChapter 16, Problem 60TQChapter 16, Problem 61TQChapter 16, Problem 62TQChapter 16, Problem 63TQChapter 16, Problem 64TQChapter 16, Problem 65TQChapter 16, Problem 66TQChapter 16, Problem 67TQChapter 16, Problem 68TQChapter 16, Problem 69TQChapter 16, Problem 70TQChapter 16, Problem 71TQChapter 16, Problem 72TQChapter 16, Problem 73TQChapter 16, Problem 74TQChapter 16, Problem 75TQ
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- The following assay based on the enzyme protein kinase A (PKA) can be used to measure cAMP level in cell. PKA is an oligomeric protein consisted of two regulatory (R) and two catalytic (C) subunits. The R2C2 complex is catalytically inactive. The binding of cAMP to the R subunits results in a conformational change such that the R subunits are released from the complex. The free catalytic (C) subunits are then enzymatically active. In the cAMP assay, the gene of the R subunit is fused with that of GFP (excitation: 465 nm, emission 545 nm) while the gene of the C subunit is fused with that of BFP (excitation: 380 nm, emission: 465 nm). These two hybrid fluorescent proteins are then expressed in the cell. Explain how such a system can be exploited to follow the concentration of cAMP in cell.arrow_forwardhelparrow_forwardCh.13/14 HW Question 14) How to figure out what type of molecule is mono-, tri-, di-, substitued or not an aromatic at all?arrow_forward
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