The reason the preparation of 1-methycyclohexanol is not possible by carbonyl reduction should be determined. Concept Introduction: In a reduction of an organic molecule, either the number of C-O bonds decreases or number of C-H bonds increases. So when a ketone or aldehyde is reduced by H 2 in the presence of Pd catalyst, C=O double bond is reduced to C-O single bond and H 2 is added across this C=O double bond. Hence, a primary alcohol is produced by an aldehyde and a secondary alcohol is produced by a ketone.

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Answer 1

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Definition Definition Organic compounds that have a carbonyl group, C=O, as their functional group. The carbonyl group in aldehydes is placed at the end of the molecular structure, which means the C=O is attached to one hydrogen atom and an alkyl group or a benzene ring. Just like all the other homologous series in organic chemistry, the naming of aldehydes uses the suffix “-al”. The general molecular formula is C n H 2n O.

Chapter 16, Problem 55P

Interpretation Introduction

Interpretation:

The reason the preparation of 1-methycyclohexanol is not possible by carbonyl reduction should be determined.

Concept Introduction:

In a reduction of an organic molecule, either the number of C-O bonds decreases or number of C-H bonds increases. So when a ketone or aldehyde is reduced by H₂ in the presence of Pd catalyst, C=O double bond is reduced to C-O single bond and H₂ is added across this C=O double bond. Hence, a primary alcohol is produced by an aldehyde and a secondary alcohol is produced by a ketone.

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Answer 2

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Definition Definition Organic compounds that have a carbonyl group, C=O, as their functional group. The carbonyl group in aldehydes is placed at the end of the molecular structure, which means the C=O is attached to one hydrogen atom and an alkyl group or a benzene ring. Just like all the other homologous series in organic chemistry, the naming of aldehydes uses the suffix “-al”. The general molecular formula is C n H 2n O.

Chapter 16, Problem 55P

Interpretation Introduction

Interpretation:

The reason the preparation of 1-methycyclohexanol is not possible by carbonyl reduction should be determined.

Concept Introduction:

In a reduction of an organic molecule, either the number of C-O bonds decreases or number of C-H bonds increases. So when a ketone or aldehyde is reduced by H₂ in the presence of Pd catalyst, C=O double bond is reduced to C-O single bond and H₂ is added across this C=O double bond. Hence, a primary alcohol is produced by an aldehyde and a secondary alcohol is produced by a ketone.

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Answer 3

Question

Definition Definition Organic compounds that have a carbonyl group, C=O, as their functional group. The carbonyl group in aldehydes is placed at the end of the molecular structure, which means the C=O is attached to one hydrogen atom and an alkyl group or a benzene ring. Just like all the other homologous series in organic chemistry, the naming of aldehydes uses the suffix “-al”. The general molecular formula is C n H 2n O.

Chapter 16, Problem 55P

Interpretation Introduction

Interpretation:

The reason the preparation of 1-methycyclohexanol is not possible by carbonyl reduction should be determined.

Concept Introduction:

In a reduction of an organic molecule, either the number of C-O bonds decreases or number of C-H bonds increases. So when a ketone or aldehyde is reduced by H₂ in the presence of Pd catalyst, C=O double bond is reduced to C-O single bond and H₂ is added across this C=O double bond. Hence, a primary alcohol is produced by an aldehyde and a secondary alcohol is produced by a ketone.

Expert Solution & Answer

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Check out a sample textbook solution

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Answer 4

Question

Definition Definition Organic compounds that have a carbonyl group, C=O, as their functional group. The carbonyl group in aldehydes is placed at the end of the molecular structure, which means the C=O is attached to one hydrogen atom and an alkyl group or a benzene ring. Just like all the other homologous series in organic chemistry, the naming of aldehydes uses the suffix “-al”. The general molecular formula is C n H 2n O.

Chapter 16, Problem 55P

Interpretation Introduction