   Chapter 2, Problem 11P

Chapter
Section
Textbook Problem

The cheetah can reach a top speed of 114 km/h (71 mi/h). While chasing its prey in a short sprint, a cheetah starts from rest and runs 45 m in a straight line, reaching a final speed of 72 km/h. (a) Determine the cheetah’s average acceleration during the short sprint, and (b) find its displacement at t = 3.5 s.

(a)

To determine
The average acceleration of a cheetah.

Explanation

Given Info: The initial velocity of the cheetah is 0 , the final velocity of the cheetah is 72km/h , and the distance covered by the cheetah is 45m .

Explanation:

Formula to calculate the average acceleration of the cheetah is,

a=vf2vi22(Δx)

Here,

a is the average acceleration of the cheetah.

vf is the final velocity of the cheetah.

vi is the initial velocity of the cheetah.

Δx is the distance covered by the cheetah.

Substitute 0 for vi , 72km/h for vf , and 45m for Δx to find a

(b)

To determine
The displacement of the cheetah at 3.5s is 27m .

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