   Chapter 2, Problem 50P

Chapter
Section
Textbook Problem

A small mailbag is released from a helicopter that is descending steadily at 1.50 m/s. After 2.00 s, (a) what is the speed of the mailbag, and (b) how far is it below the helicopter? (c) What are your answers to parts (a) and (b) if the helicopter is rising steadily at 1.50 m/s?

(a)

To determine
The magnitude of the velocity of the mailbag.

Explanation

Given Info: The initial velocity of the mailbag is 1.50m/s , the acceleration of the mailbag is 9.80m/s2 , and the time taken is 2.00s .

Explanation:

The formula used to calculate final velocity of the mailbag is,

vbag=v0+at

Here,

vbag is the final velocity of the mailbag

v0 is the initial velocity of the mailbag

a is the acceleration of the mailbag

t is the time taken

Substitute 1.50m/s for v0 , 2

(b)

To determine
The distance separating the package and the helicopter.

(c)

To determine
Answers to part (a) and (b) if the helicopter is rising steadily at 1.50m/s .

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