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Concept explainers
a.
To determine:
Whether the blue, red or green line represents A1, B1 and C1 in the given graph.
Introduction:
The deleterious mutations disrupt the important functions such as the activity of an enzyme encoded by a gene. Beneficial mutations are the type of mutations that provide a selective advantage to an organism.
b.
To determine:
The reason that the allele represented by green line goes to fixation slower than the allele represented by the red line.
Introduction:
Neutral mutations are the type of mutations that produce polymorphisms. These polymorphisms neither provide benefit nor harm the organism. This is because the original and mutant alleles are selectively equivalent.
c.
To determine:
The reason that the allele represented by the blue line goes to fixation slowly as compared to the alleles represented by the red or green line.
Introduction:
Genetic drift occurs faster in small populations as compared to the large population. If the population size is finite, the level of genetic drift occurs based on the
d.
To determine:
The changes in the given graph if the population has 1000 individuals.
Introduction:
Fitness is an individual’s ability to survive and transmit its genes to the next generation. Fitness is associated with each genotype. The fitness can be measured by considering all the organisms of a particular genotype.
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Chapter 20 Solutions
Genetics: From Genes to Genomes, 5th edition
- In corn, yellow kernel color is governed by a dominant allele for white color, W, and by its recessive allele, w, . A random sample of 100 kernels from a population that is in equilibrium reveals that 9 are yellow and 91 are white. What are the frequencies of the yellow and white alleles in this population? What is the percentage of the heterozygotes?arrow_forwardThe B locus has two alleles B and b with frequencies of0.95 and 0.05, respectively, in a population in the currentgeneration. The genotypic fitnesses at this locus are wB/B= 1.0, wB/ b = 1.0, and wb / b = 0.0a. What will the frequency of the b allele be in twogenerations?b. What will the frequency of the b allele be in twogenerations if the fitnesses were wB/B = 1.0, wB/ b = 0.0,and wb / b = 0.0?c. Explain why there is a difference in the rate ofchange for the frequency of the b allele under parts (a)and (b) of this problemarrow_forwardIn corn, kernel color is governed by a dominant allele for white color (W) and by a recessive allele for yellow (w). A random sample of 152 kernels from a population that is in Hardy- Weinberg equilibrium reveals that 35 kernels are yellow and 117 kernels are white. What is the frequency of individuals with the homozygous dominant genotype?arrow_forward
- Which of the following statements does NOT apply to the Hardy-Weinberg expression: p2 + 2pq + q2? Group of answer choices p2 is the frequency of individuals with the homozygous recessive genotype. 2pq is the frequency of individuals with the heterozygous genotype. It can be used to determine the genotype and allele frequencies of the previous and the next generations. Knowing either p2 or q2, you can calculate all the other frequenciesarrow_forwardEye color in a species of fruitfly is determined by a single locus with two alleles: E and e. EE individuals have red eyes, Ee have pink eyes, and ee individuals have brown eyes. In a lab population that is in Hardy- Weinberg equilibrium, we count 34 flies with brown eyes out of 144. How many flies can you expect to have red eyes? Round your answer to the closest integer value.arrow_forwardAssume that the frequency of gene B in a hypothetical population Is 0.63, that there are only two alleles (B and b) of the gee in the population, that allele B is dominant over allele b, that neither allele has a selective advantage over the other, and that the population is at equilibrium with regard to this particular gene. And how many individuals in this population are expected to be of genotype BB according to the Hardy-Weinberg formula? (Assume that the total population size is 150) 71 52 118 60 131arrow_forward
- Consider a population of 2500 individuals at Hardy-Weinberg equilibrium. There are two loci, each with two alleles, in linkage equilibrium with one another. - At the first locus the alleles "A" and "e" cause two distinct phenotypes; individuals who are "AA" or "Ae" are Alabaster whereas individuals who are "ee" are ebony. -At the second locus the alleles "L" and "S" cause three distinct phenotypes. Individuals who are "LL" are large, individuals who are "LS" are medium and individuals who are "SS" are small. If we determine that there are 1029 alabaster large and 196 ebony large individuals: (a) What is the frequency of the "A" allele? Round to nearest 0.001. (b) How many copies of the "e" allele exist in the population? Round to nearest integer. (c) What proportion of the population are ebony medium individuals? Round to nearest 0.001. (d) How many individuals will be homozygous at both loci? Round to nearest integer. (e) If the environment suddenly changed and ebony individuals…arrow_forwardEye color in a species of fruitfly is determined by a single locus with two alleles: E and e. EE individuals have red eyes, Ee have pink eyes, and ee individuals have brown eyes. In a lab population that is in Hardy–Weinberg equilibrium, we count 27 flies with brown eyes out of 164. How many flies can you expect to have red eyes? Round your answer to the closest integer value.arrow_forwardPretend that you are comparing the actual genotype distribution for a population with the distribution of genotypes predicted by the Hardy-Weinberg theorem. So your hypothesis is that the population is in Hardy-Weinberg equilibrium (i.e. that actual population data fit the Hardy-Weinberg expectations). If you carry out a chisquare goodness of fit test and calculate a total chisquare value of 0.03 with 1 degree of freedom (see table), what does this mean? (select all true statements)a) The data do NOT fit the hypothesized distribution.b) The data do fit the hypothesized distribution well enough, so we accept the hypothesis at this time (i.e. we cannot reject the hypothesis). c) The probability that the data came from a population in Hardy-Weinberg equilibrium is too small, so we reject the hypothesis.d) The probability that the data came from a population in Hardy-Weinberg equilibrium is too big, so we reject the hypothesis.e) The data support Hardy-Weinberg expectations – there is no…arrow_forward
- In a population of 200 people, an allele F has a frequency of 84%. What is the frequency of allele f? Using the Hardy-Weinberg equation, estimate the numbers of homozygous dominant, heterozygous, and homozygous recessive genotypes. (Remember that the formula is: p2 + 2pq + q2 = 1, where p represents the dominant allele and q represents the recessive allele.) *Be sure to account for all 200 people in the population.arrow_forwardEye color in a species of fruitfly is determined by a single locus with two alleles: E and e. EE individuals have red eyes, Ee have pink eyes, and ee individuals have brown eyes. In a lab population that is in Hardy- Weinberg equilibrium, we count 30 flies with brown eyes out of 109. How many flies can you expect to have red eyes? Round your answer to the closest integer value. Your Answer:arrow_forwardIf 120 of 200 alleles are dominant alleles, then what percentage of the alleles are dominant alleles? A-12% B-40% C-60% D-120% What percentage of the alleles are recessive alleles? E-8% F-40% G-60% H-80% Which of the terms of the Hardy-Weinberg equations represents the frequency of the recessive allele in the gene pool? A-p^2 B-p C-2pq D-q^2arrow_forward
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