(a) Interpretation: The product obtained on Hofmann rearrangement reaction of 2 − methylpropanamide in ethanol is to be stated. Concept introduction: Hofmann rearrangement reaction is the conversion reaction of the primary amide to a primary amine with the loss of one carbon chain. It requires basic conditions. The reaction of sodium hydroxide with bromine forms sodium hypobromite as an intermediate in situ . The intermediate formed in Hofmann reaction reacts with ethanol to form a carbamate, then the reaction is known as Curtius azide reaction.

Question

Want to see the full answer?

Answer 1

Question

Chapter 23, Problem 23.40P

Interpretation Introduction

(a)

Interpretation:

The product obtained on Hofmann rearrangement reaction of 2−methylpropanamide in ethanol is to be stated.

Concept introduction:

Hofmann rearrangement reaction is the conversion reaction of the primary amide to a primary amine with the loss of one carbon chain. It requires basic conditions. The reaction of sodium hydroxide with bromine forms sodium hypobromite as an intermediate in situ. The intermediate formed in Hofmann reaction reacts with ethanol to form a carbamate, then the reaction is known as Curtius azide reaction.

Interpretation Introduction

(b)

Interpretation:

The product obtained on Hofmann rearrangement reaction of 2−methylpropanamide in aqueous NaOH is to be stated.

Concept introduction:

Hofmann rearrangement reaction is the conversion reaction of the primary amide to a primary amine with the loss of one carbon chain. It requires basic conditions. The reaction of sodium hydroxide with bromine forms sodium hypobromite as an intermediate in situ.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

Predict the products formed when cyclohexanone reacts with the following reagents.(a) CH3NH2, H

Explain why methyl trifluoroacetate, CF3CO2CH3, is more reactive than methyl acetate, CH3CO2CH3, in nucleophilic acyl substitution reactions.

4) Rank the following compounds in order of increasing reactivity (least to most reactive) with respect to acyl substitution. I. methyl benzoate II. benzoylchloride III. benzamide III < | < ||

Answer 2

Question

Chapter 23, Problem 23.40P

Interpretation Introduction

(a)

Interpretation:

The product obtained on Hofmann rearrangement reaction of 2−methylpropanamide in ethanol is to be stated.

Concept introduction:

Hofmann rearrangement reaction is the conversion reaction of the primary amide to a primary amine with the loss of one carbon chain. It requires basic conditions. The reaction of sodium hydroxide with bromine forms sodium hypobromite as an intermediate in situ. The intermediate formed in Hofmann reaction reacts with ethanol to form a carbamate, then the reaction is known as Curtius azide reaction.

Interpretation Introduction

(b)

Interpretation:

The product obtained on Hofmann rearrangement reaction of 2−methylpropanamide in aqueous NaOH is to be stated.

Concept introduction:

Hofmann rearrangement reaction is the conversion reaction of the primary amide to a primary amine with the loss of one carbon chain. It requires basic conditions. The reaction of sodium hydroxide with bromine forms sodium hypobromite as an intermediate in situ.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 3

Question

Chapter 23, Problem 23.40P

Interpretation Introduction

(a)

Interpretation:

The product obtained on Hofmann rearrangement reaction of 2−methylpropanamide in ethanol is to be stated.

Concept introduction:

Hofmann rearrangement reaction is the conversion reaction of the primary amide to a primary amine with the loss of one carbon chain. It requires basic conditions. The reaction of sodium hydroxide with bromine forms sodium hypobromite as an intermediate in situ. The intermediate formed in Hofmann reaction reacts with ethanol to form a carbamate, then the reaction is known as Curtius azide reaction.

Interpretation Introduction

(b)

Interpretation:

The product obtained on Hofmann rearrangement reaction of 2−methylpropanamide in aqueous NaOH is to be stated.

Concept introduction:

Hofmann rearrangement reaction is the conversion reaction of the primary amide to a primary amine with the loss of one carbon chain. It requires basic conditions. The reaction of sodium hydroxide with bromine forms sodium hypobromite as an intermediate in situ.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 4

Question

Chapter 23, Problem 23.40P

Interpretation Introduction

(a)

Interpretation:

The product obtained on Hofmann rearrangement reaction of 2−methylpropanamide in ethanol is to be stated.

Concept introduction:

Hofmann rearrangement reaction is the conversion reaction of the primary amide to a primary amine with the loss of one carbon chain. It requires basic conditions. The reaction of sodium hydroxide with bromine forms sodium hypobromite as an intermediate in situ. The intermediate formed in Hofmann reaction reacts with ethanol to form a carbamate, then the reaction is known as Curtius azide reaction.

Interpretation Introduction

(b)

Interpretation:

The product obtained on Hofmann rearrangement reaction of 2−methylpropanamide in aqueous NaOH is to be stated.

Concept introduction:

Hofmann rearrangement reaction is the conversion reaction of the primary amide to a primary amine with the loss of one carbon chain. It requires basic conditions. The reaction of sodium hydroxide with bromine forms sodium hypobromite as an intermediate in situ.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 5

Chapter 23, Problem 23.40P

Interpretation Introduction

(a)

Interpretation:

The product obtained on Hofmann rearrangement reaction of 2−methylpropanamide in ethanol is to be stated.

Concept introduction:

Hofmann rearrangement reaction is the conversion reaction of the primary amide to a primary amine with the loss of one carbon chain. It requires basic conditions. The reaction of sodium hydroxide with bromine forms sodium hypobromite as an intermediate in situ. The intermediate formed in Hofmann reaction reacts with ethanol to form a carbamate, then the reaction is known as Curtius azide reaction.

Interpretation Introduction

(b)

Interpretation:

The product obtained on Hofmann rearrangement reaction of 2−methylpropanamide in aqueous NaOH is to be stated.

Concept introduction:

Hofmann rearrangement reaction is the conversion reaction of the primary amide to a primary amine with the loss of one carbon chain. It requires basic conditions. The reaction of sodium hydroxide with bromine forms sodium hypobromite as an intermediate in situ.

Answer 6

Chapter 23, Problem 23.40P

Interpretation Introduction

(a)

Interpretation:

The product obtained on Hofmann rearrangement reaction of 2−methylpropanamide in ethanol is to be stated.

Concept introduction:

Hofmann rearrangement reaction is the conversion reaction of the primary amide to a primary amine with the loss of one carbon chain. It requires basic conditions. The reaction of sodium hydroxide with bromine forms sodium hypobromite as an intermediate in situ. The intermediate formed in Hofmann reaction reacts with ethanol to form a carbamate, then the reaction is known as Curtius azide reaction.

Answer 7

Chapter 23, Problem 23.40P

Interpretation Introduction

(a)

Interpretation:

The product obtained on Hofmann rearrangement reaction of 2−methylpropanamide in ethanol is to be stated.

Concept introduction:

Hofmann rearrangement reaction is the conversion reaction of the primary amide to a primary amine with the loss of one carbon chain. It requires basic conditions. The reaction of sodium hydroxide with bromine forms sodium hypobromite as an intermediate in situ. The intermediate formed in Hofmann reaction reacts with ethanol to form a carbamate, then the reaction is known as Curtius azide reaction.

Answer 8

Interpretation Introduction

(b)

Interpretation:

The product obtained on Hofmann rearrangement reaction of 2−methylpropanamide in aqueous NaOH is to be stated.

Concept introduction:

Hofmann rearrangement reaction is the conversion reaction of the primary amide to a primary amine with the loss of one carbon chain. It requires basic conditions. The reaction of sodium hydroxide with bromine forms sodium hypobromite as an intermediate in situ.

Answer 9

Interpretation Introduction

(b)

Interpretation:

The product obtained on Hofmann rearrangement reaction of 2−methylpropanamide in aqueous NaOH is to be stated.

Concept introduction:

Hofmann rearrangement reaction is the conversion reaction of the primary amide to a primary amine with the loss of one carbon chain. It requires basic conditions. The reaction of sodium hydroxide with bromine forms sodium hypobromite as an intermediate in situ.

Answer 10

Expert Solution & Answer

Answer 11

Expert Solution & Answer

Answer 12

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 13

Ch. 23 - Prob. 23.1P Ch. 23 - Prob. 23.2P Ch. 23 - Prob. 23.3P Ch. 23 - Prob. 23.4P Ch. 23 - Prob. 23.5P Ch. 23 - Prob. 23.6P Ch. 23 - Prob. 23.7P Ch. 23 - Prob. 23.8P Ch. 23 - Prob. 23.9P Ch. 23 - Prob. 23.10P

Solution Summary: The author explains the product obtained on Hofmann rearrangement reaction of 2-methylpropanamide in ethanol.

Concept explainers

Want to see the full answer?

Chapter 23 Solutions