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Concept explainers
(a)
Interpretation:
The structure of a thymine residue that exists after
Concept introduction:
DNA stands for deoxyribonucleic acid, is a biological macromolecule. DNA contains double helical strands along with the complementary base pairs. The four complementary bases of DNA are adenine (A), thymine (T), guanine (G) and cytosine (C). In the formation of recombinant DNA, the restriction enzymes are involved to cut the particular region in the DNA molecule. This region is known as restriction.
(b)
Interpretation:
The reason as to why
Concept introduction:
DNA stands for deoxyribonucleic acid, is a biological macromolecule. DNA contains double helical strands along with the complementary base pairs. The four complementary bases of DNA are adenine (A), thymine (T), guanine (G) and cytosine (C). In the formation of recombinant DNA, the restriction enzymes are involved to cut the particular region in the DNA molecule. This region is known as restriction.
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Chapter 26 Solutions
EBK ORGANIC CHEMISTRY
- 22-42 (a) How many atoms of the peptide bond lie in the same plane? (b) Which atoms are they?arrow_forward22-97 Gelatin is derived from collagen by denaturation. Is a gelatin dessert likely to be a good source of dietary protein?arrow_forwardSketch the structures of ribose and deoxyribose ‐‐‐ what is the structural difference? Which nucleotides are associated with DNA? Which ones with RNA? Why must detergent be added to liberate the DNA? What parts of the cell contain DNA?arrow_forward
- (a) The isoelectric point (pI) of phenylalanine is pH 5.5. Draw the structure of the major form of phenylalanine at pHvalues of 1, 5.5, and 11.(b) The isoelectric point of histidine is pH 7.6. Draw the structures of the major forms of histidine at pH values of 1, 4,7.6, and 11. Explain why the nitrogen in the histidine ring is a weaker base than the a-amino group.(c) The isoelectric point of glutamic acid is pH 3.2. Draw the structures of the major forms of glutamic acid at pH valuesof 1, 3.2, 7, and 11. Explain why the side-chain carboxylic acid is a weaker acid than the acid group next to thea-carbon atomarrow_forwardPlease write the chemical reaction in fluorescence Riboflavin (Vitamin B2) + Acetic Acid C17H20N4O6 + CH3COOH----->arrow_forwardh) Specify the absolute (R/S) configuration of the amino group in structure IV. (i) If the substituents in structures I, IV and V were identical (all OH or all NH2), which structure would result in a meso compound? (j) If each hydroxy group for structures I, II and VI were replaced with another amino group, which compound would be made optically inactive?arrow_forward
- Exposure to nitrous acid (see Section 19-16), sometimes found in cells, can convert cytosine to uracil.(a) Propose a mechanism for this conversion.(b) Explain how this conversion would be mutagenic upon replication.(c) DNA generally includes thymine, rather than uracil (found in RNA). Based on this fact, explain why the nitrous-acidinduced mutation of cytosine to uracil is more easily repaired in DNA than it is in RNA.*arrow_forwardErwin Chargaff’s discovery that DNA contains equimolar amounts of guanine and cytosine and also equimolar amounts ofadenine and thymine has come to be known as Chargaff’s rule:G = C and A = T(a) Does Chargaff’s rule imply that equal amounts of guanine and adenine are present in DNA? That is, does G = A?(b) Does Chargaff’s rule imply that the sum of the purine residues equals the sum of the pyrimidine residues? That is,does A + G = C + T?(c) Does Chargaff’s rule apply only to double-stranded DNA, or would it also apply to each individual strand if thedouble helical strand were separated into its two complementary strands?arrow_forwardResearchers analysed a glycopeptide (a peptide carrying one or several oligosaccharide groups) and determined both the sequence of the peptide and the sequence of the sugar molecule. The latter was identified as a diholoside coupled to the peptide by an osidic bond. The systematic name of this sugar is: B-D-glucopyranosyl-(1→4)-ß-D-galactopyranose. : Represent the chemical formula of this diholoside in a way that all oses are Question 1 represented according to the Haworth convention. Apart from the furane and/or pyrane cycles all atoms of this molecule must be given.arrow_forward
- draw out the true structures of aspartic acid at (a) pH = 1.52, (b) = 7.35, (c) pH = 9.95arrow_forwardAn enzyme catalyzes the hydrolysis of an ester with a certain activity, but this activity is lost in a 3 M urea solution. What is the most likely explanation for the loss of activity? (A) Urea binds to the active site of the enzyme competitively with the substrate. (B) Urea causes the cleavage of the peptide bonds in the enzyme. (C) Urea causes the enzyme to denature and lose its specific three-dimensional shape. (D) Urea reacts with disulfide bonds in the enzyme.arrow_forwardwrite же тирас Name 1+ [20 (1₂0) (10) [6 (MA), (NHL)₂_]) [H₂ CHP), ON JON Each of the Followingarrow_forward
- Introduction to General, Organic and BiochemistryChemistryISBN:9781285869759Author:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar TorresPublisher:Cengage Learning
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