College Physics
College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
bartleby

Concept explainers

bartleby

Videos

Textbook Question
Book Icon
Chapter 4, Problem 37P

(a) An elevator of mass m moving upward has two forces acting on it: the upward force of tension in the cable and the downward force due to gravity. When the elevator is accelerating upward, which is greater, T or w? (b) When the elevator is moving at a constant velocity upward, which is greater, T or w? (c) When the elevator is moving upward, but the acceleration is downward, which is greater, T or w? (d) Let the elevator have a mass of 1 500 kg and an upward acceleration of 2.5 m/s2. Find T. Is your answer consistent with the answer to part (a)? (e) The elevator of part (d) now moves with a constant upward velocity of 10 m/s. Find T. Is your answer consistent with your answer to part (b)? (f) Having initially moved upward with a constant velocity, the elevator begins to accelerate downward at 1.50 m/s2. Find T. Is your answer consistent with your answer to part (c)?

(a)

Expert Solution
Check Mark
To determine

The tension on the cable.

Answer to Problem 37P

Tension (T) on the cable should be greater than the weight.

Explanation of Solution

Given Info: Mass of the block is m.

Weight of the elevator is,

  W=mg

  • g is the acceleration due to gravity.
  • m is  the mass of the block.

Conclusion:

The force of gravity acts downwards. For the elevator to move upwards,T>W.

(b)

Expert Solution
Check Mark
To determine

The tension on the cable.

Answer to Problem 37P

Tension (T) on the cable is equal to the weight.

Explanation of Solution

According to Newton’s second law, force is equal to the product of mass and acceleration.

Force is expressed as,

  F=ma

  • a is the acceleration.
  • m is  the mass of the block.

Conclusion:

Acceleration is the rate of change of velocity. Since, velocity is constant, the acceleration is zero. Therefore, the total force is zero. As a result, the tension equals the weight of the elevator.

(c)

Expert Solution
Check Mark
To determine

The tension on the cable.

Answer to Problem 37P

Tension (T) on the cable should be lesser than the weight.

Explanation of Solution

Given Info: Mass of the block is m.

Weight of the elevator is,

  W=mg

  • g is the acceleration due to gravity.
  • m is  the mass of the block.

Conclusion:

The force of gravity acts downwards. For the elevator to move downwards, T<W.

(d)

Expert Solution
Check Mark
To determine

The tension on the cable.

Answer to Problem 37P

Tension (T) on the cable should be greater than the weight.

Explanation of Solution

Tension on the cable is,

  T=m(g+a)

  • g is the acceleration due to gravity.
  • m is  the mass of the block.
  • a is the acceleration.

Weight of the elevator is,

  W=mg

  • g is the acceleration due to gravity.
  • m is  the mass of the block.

Substitute 1200 kg for m, 9.8ms2 for g and 2.50ms2 for a in the expression for T.

T=(1200kg)(9.8ms2+2.50ms2)=14760N

Substitute 1200 kg for m and 9.8ms2 for g in the expression for W.

W=(1200kg)(9.8ms2)=11760N

Conclusion:

Tension on the cable is 14760 N. The weight of the elevator is 11760 N. Therefore,

T > W.

(e)

Expert Solution
Check Mark
To determine

The tension on the cable.

Answer to Problem 37P

Tension (T) on the cable is equal to the weight.

Explanation of Solution

Tension on the cable is,

  T=m(g+a)

  • g is the acceleration due to gravity.
  • m is  the mass of the block.
  • a is the acceleration.

Acceleration is the rate of change of velocity. Since, velocity is constant, the acceleration is zero

Weight of the elevator is,

  W=mg

  • g is the acceleration due to gravity.
  • m is  the mass of the block.

Substitute 1200 kg for m, 9.8ms2 for g and 0ms2 for a in the expression for T.

T=(1200kg)(9.8ms2+0ms2)=11760N

Substitute 1200 kg for m and 9.8ms2 for g in the expression for W.

T=(1200kg)(9.8ms2)=11760N

Conclusion:

Therefore, T = W. It is consistent with (b).

(f)

Expert Solution
Check Mark
To determine

The tension on the cable.

Answer to Problem 37P

Tension (T) on the cable should be lesser than the weight.

Explanation of Solution

Tension on the cable is,

  T=m(ga)

  • g is the acceleration due to gravity.
  • m is  the mass of the block.
  • a is the acceleration.

Weight of the elevator is,

  W=mg

  • g is the acceleration due to gravity.
  • m is  the mass of the block.

Substitute 1200 kg for m, 9.8ms2 for g and 2.50ms2 for a in the expression for T.

T=(1200kg)(9.8ms22.50ms2)=8760N

Substitute 1200 kg for m and 9.8ms2 for g in the expression for W.

T=(1200kg)(9.8ms2)=11760N

Conclusion:

Therefore, T<W. It is consistent with (c).

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!
Students have asked these similar questions
An elevator of mass m moving upward has two forces acting on it: the upward force of tension in the cable and the downward force due to gravity. When the elevator is accelerating upward, which is greater, T or w? Or are both forces equal?
the coefficient of static friction between block A and a horizontal floor is 0.320, and the coefficient of static friction between block B and the floor is 0.300. The mass of each block is 2.00kg,and they are connected together by a cord. If a horizontal force F pulling on block B is slowly increased ,in a direction parallel to the connectin cord,until the block start sliding ,what is the magnitude of F at the instant that they start to slide?
A 100 N force, directed at an angle u above a horizontal floor, is applied to a 25.0 kg chair sitting on the floor. If u =0, what are (a) the horizontal component Fh of the applied force and (b) the magnitude FN of the normal force of the floor on the chair? If u =30.0, what are (c) Fh and (d) FN? If u =60.0, what are (e) Fh and (f) FN? Now assume that the coefficient of static friction between chair and floor is 0.420. Does the chair slide or remain at rest if u is (g) 0, (h) 30.0, and (i) 60.0?

Chapter 4 Solutions

College Physics

Ch. 4 - A space explorer is moving through space far from...Ch. 4 - (a) If gold were sold by weight, would you rather...Ch. 4 - If you push on a heavy box that is at rest, you...Ch. 4 - A ball is held in a persons hand. (a) Identify all...Ch. 4 - A weight lifter stands on a bathroom scale. (a) As...Ch. 4 - (a) What force causes an automobile to move? (b) A...Ch. 4 - If only one force acts on an object, can it be in...Ch. 4 - In the: motion picture It Happened One Night...Ch. 4 - Analyze the motion of a rock dropped in water in...Ch. 4 - Identify the action-reaction pairs in the...Ch. 4 - Draw a free-body diagram for each of the following...Ch. 4 - In a tug-of-war between two athletes, each pulls...Ch. 4 - Suppose you are driving a car at a high speed. Why...Ch. 4 - As a block slides down a frictionless incline,...Ch. 4 - A crate remains stationary after it has been...Ch. 4 - In Figure 4.4, a locomotive has broken through the...Ch. 4 - If an object is in equilibrium, which of the...Ch. 4 - A truck loaded with sand accelerates along a...Ch. 4 - A large crate of mass m is placed on the back of a...Ch. 4 - Which of the following statements are true? (a) An...Ch. 4 - A woman is standing on the Earth. In terms of...Ch. 4 - An exoplanet has twice the mass and half the...Ch. 4 - Choose the best answer. A car traveling at...Ch. 4 - The heaviest invertebrate is the giant squid,...Ch. 4 - A football punter accelerates a football from rest...Ch. 4 - A 6.0-kg object undergoes an acceleration of 2.0...Ch. 4 - One or more external forces are exerted on each...Ch. 4 - A bag of sugar weighs 5.00 lb on Earth. What would...Ch. 4 - A freight train has a mass of 1.5 107 kg. If the...Ch. 4 - Four forces act on an object, given by A = 40.0 N...Ch. 4 - Consider a solid metal sphere (S) a few...Ch. 4 - As a fish jumps vertically out of the water,...Ch. 4 - A 5.0-g bullet leaves the muzzle of a rifle with a...Ch. 4 - A boat moves through the water with two forces...Ch. 4 - Two forces are applied to a car in an effort to...Ch. 4 - A 970.-kg car starts from rest on a horizontal...Ch. 4 - An object of mass m is dropped from the roof of a...Ch. 4 - After falling from rest from a height of 30.0 m, a...Ch. 4 - The force exerted by the wind on the sails of a...Ch. 4 - A force of 30.0 N is applied in the positive...Ch. 4 - What would be the acceleration of gravity at the...Ch. 4 - Calculate the magnitude of the normal force on a...Ch. 4 - A horizontal force of 95.0 N is applied to a...Ch. 4 - A car of mass 875 kg is traveling 30.0 m/s when...Ch. 4 - A student of mass 60.0 kg, starting at rest,...Ch. 4 - A 1.00 103-N crate is being pushed across a level...Ch. 4 - A block of mass m = 5.8 kg is pulled up a = 25...Ch. 4 - A rocket takes off from Earths surface,...Ch. 4 - A man exerts a horizontal force of 125 N on a...Ch. 4 - A horse is harnessed to a sled having a mass of...Ch. 4 - A block of mass 55.0 kg rests on a slope having an...Ch. 4 - A dockworker loading crates on a ship finds that a...Ch. 4 - Suppose the coefficient of static friction between...Ch. 4 - The coefficient of static friction between the...Ch. 4 - Two identical strings making an angle of = 30.0...Ch. 4 - A 75-kg man standing on a scale in an elevator...Ch. 4 - A crate of mass m = 32 kg rides on the bed of a...Ch. 4 - (a) Find the tension in each cable supporting the...Ch. 4 - The distance between two telephone poles is 50.0...Ch. 4 - (a) An elevator of mass m moving upward has two...Ch. 4 - A certain orthodontist uses a wire brace to align...Ch. 4 - A 150-N bird feeder is supported by three cables...Ch. 4 - The leg and cast in Figure P4.40 weigh 220 N (w1)....Ch. 4 - A 276-kg glider is being pulled by a 1 950-kg jet...Ch. 4 - A crate of mass 45.0 kg is being transported on...Ch. 4 - Consider a large truck carrying a heavy load, such...Ch. 4 - A student decides to move a box of books into her...Ch. 4 - An object falling under the pull of gravity is...Ch. 4 - A 3.00-kg block starts from rest at the top of a...Ch. 4 - To meet a U.S. Postal Service requirement,...Ch. 4 - A block of mass 12.0 kg is sliding at an initial...Ch. 4 - The person in Figure P4.49 weighs 170. lb. Each...Ch. 4 - A car is traveling at 50.0 km/h on a flat highway....Ch. 4 - A 5.0-kg bucket of water is raised from a well by...Ch. 4 - A hockey puck struck by a hockey stick is given an...Ch. 4 - A setup similar to the one shown in Figure P4.53...Ch. 4 - An Atwoods machine (Fig. 4.38) consists of two...Ch. 4 - A block of mass m1 = 16.0 kg is on a frictionless...Ch. 4 - Two blocks each of mass m are fastened to the top...Ch. 4 - Two blocks of masses m and 2m are held in...Ch. 4 - The systems shown in Figure P4.58 are in...Ch. 4 - Assume the three blocks portrayed in Figure P4.59...Ch. 4 - Two packing crates of masses 10.0 kg and 5.00 kg...Ch. 4 - A 1.00 103 car is pulling a 300.-kg trailer....Ch. 4 - Two blocks of masses m1 and m2 (m1 m2) are placed...Ch. 4 - In Figure P4.63, the light, taut, unstretchable...Ch. 4 - An object with mass m1 = 5.00 kg rests on a...Ch. 4 - Objects with masses m1 = 10.0 kg and m2 = 5.00 kg...Ch. 4 - Two objects with masses of 3.00 kg and 5.00 kg are...Ch. 4 - In Figure P4.64, m1 = 10. kg and m2 = 4.0 kg. The...Ch. 4 - A block of mass 3m is placed on a frictionless...Ch. 4 - A 15.0-lb block rests on a horizontal floor, (a)...Ch. 4 - Objects of masses m1 = 4.00 kg and m2 = 9.00 kg...Ch. 4 - Two blocks each of mass m = 3.50 kg are fastened...Ch. 4 - As a protest against the umpires calls, a baseball...Ch. 4 - Three objects are connected on a table as shown in...Ch. 4 - (a) What is the minimum force of friction required...Ch. 4 - (a) What is the resultant force exerted by the two...Ch. 4 - A woman at an airport is towing her 20.0-kg...Ch. 4 - A boy coasts down a hill on a sled, reaching a...Ch. 4 - Three objects are connected by light strings as...Ch. 4 - A box rests on the back of a truck. The...Ch. 4 - A high diver of mass 70.0 kg steps off a board...Ch. 4 - A frictionless plane is 10.0 m long and inclined...Ch. 4 - Measuring coefficients of friction A coin is...Ch. 4 - A 2.00-kg aluminum block and a 6.00-kg copper...Ch. 4 - On an airplanes takeoff, the combined action of...Ch. 4 - Two boxes of fruit on a frictionless horizontal...Ch. 4 - A sled weighing 60.0 N is pulled horizontally...Ch. 4 - A car accelerates down a hill (Fig. P4.87), going...Ch. 4 - An inventive child wants to reach an apple in a...Ch. 4 - The parachute on a race car of weight 8 820 N...Ch. 4 - A fire helicopter carries a 620-kg bucket of water...Ch. 4 - The board sandwiched between two other boards in...Ch. 4 - A 72-kg man stands on a spring scale in an...
Knowledge Booster
Background pattern image
Physics
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.
Similar questions
SEE MORE QUESTIONS
Recommended textbooks for you
Text book image
Principles of Physics: A Calculus-Based Text
Physics
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
Text book image
University Physics Volume 1
Physics
ISBN:9781938168277
Author:William Moebs, Samuel J. Ling, Jeff Sanny
Publisher:OpenStax - Rice University
Newton's Second Law of Motion: F = ma; Author: Professor Dave explains;https://www.youtube.com/watch?v=xzA6IBWUEDE;License: Standard YouTube License, CC-BY