   # Boron consists of two isotopes, 10 B and 11 B. Chlorine also has two isotopes, 35 Cl and 37 Cl. Consider the mass spectrum of BC1 3 . How many peaks would be present, and what approximate mass would each peak correspond to in the BCl 3 mass spectrum? ### Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781305079243

#### Solutions

Chapter
Section ### Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781305079243
Chapter 5, Problem 128AE
Textbook Problem
318 views

## Boron consists of two isotopes, 10B and 11B. Chlorine also has two isotopes, 35Cl and 37Cl. Consider the mass spectrum of BC13. How many peaks would be present, and what approximate mass would each peak correspond to in the BCl3 mass spectrum?

Interpretation Introduction

Interpretation: The number of peaks and the mass of each peak in the mass spectrum of BCl3 are to be calculated.

Concept introduction: The isotopes are defined as the elements having same number of protons in the nucleus that they have the same atomic number but having different atomic masses. The properties of the isotope of a single element are identical. Mass spectrum is a plot between mass to charge ratio. It represents the distribution of ions in a sample by using mass spectrophotometer.

### Explanation of Solution

Explanation

Given

The two isotopes of Boron are 10B and 11B and the two isotopes of Chlorine are 35Cl and 37Cl . respectively.

The number of peaks in the mass spectrum of BCl3 is calculated by using the possible combinations of the given four isotopes. The isotopes of Boron are 10B and 11B . The number of peaks is calculated in such a way that each peak contains three atoms of chlorine and one Boron atom with their respective isotopes. By using each isotope of Boron with Chlorine isotopes the number of peaks in the mass spectrum of BCl3 is calculated.

Using 10 the possible peaks with the three Chlorine atoms having isotopes 35Cl and 37Cl is,

10B35Cl3

10B35Cl237Cl

10B35Cl37Cl2

10B37Cl3

Similarly, by using  11B the possible peaks with the three Chlorine atoms having isotopes 35Cl and 37Cl is,

11B35Cl3

11B35Cl237Cl

11B35Cl37Cl2

11B37Cl3

Hence, there are eight possible combinations of peaks in the mass spectrum of BCl3 .

The mass of each peak is calculated by using the expression,

Total Mass of peak=(Number of B atoms×Atomic Mass of B+Number of Cl atoms×Atomic Mass of Cl)

By using 10 the mass of each peak is calculated as,

Substitute the values of atomic mass of 10 and the atomic mass of 35Cl and 37Cl in the above expression

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