   # What amount (moles) of compound is present in 1.00 g of each of the compounds in Exercise 52? ### Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781305079243

#### Solutions

Chapter
Section ### Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781305079243
Chapter 5, Problem 54E
Textbook Problem
1363 views

## What amount (moles) of compound is present in 1.00 g of each of the compounds in Exercise 52?

(a)

Interpretation Introduction

Concept introduction: The atomic mass is defined as the sum of number of protons and number of neutrons.

The amount of substance containing 12g of pure carbon is called a mole. One mole of atoms always contains 6.022×1023 atoms. The number of moles is also called Avogadro’s number.

Hence,

(6.022×1023 atoms)(12u1atom)=12g1u=16.022×1023 g

Also the formula of number of moles is

Molesofatom=massofatomatomicmass

To determine: The amount (moles) of compound in 1.00g of P4O6 .

### Explanation of Solution

Given

The mass of P4O6 is 1.00g .

The molar mass of P4O6 is,

123.892g/mol+95.994g/mol=219.886g/mol

The amount of compound P4O6 is 1.00g is calculated as,

MolesofP4O6atom=massofP4O6atomic

(b)

Interpretation Introduction

Concept introduction: The atomic mass is defined as the sum of number of protons and number of neutrons.

The amount of substance containing 12g of pure carbon is called a mole. One mole of atoms always contains 6.022×1023 atoms. The number of moles is also called Avogadro’s number.

Hence,

(6.022×1023 atoms)(12u1atom)=12g1u=16.022×1023 g

Also the formula of number of moles is

Molesofatom=massofatomatomicmass

To determine: The amount (moles) of compound in 1.00g of Ca3(PO4)2 .

(c)

Interpretation Introduction

Concept introduction: The atomic mass is defined as the sum of number of protons and number of neutrons.

The amount of substance containing 12g of pure carbon is called a mole. One mole of atoms always contains 6.022×1023 atoms. The number of moles is also called Avogadro’s number.

Hence,

(6.022×1023 atoms)(12u1atom)=12g1u=16.022×1023 g

Also the formula of number of moles is

Molesofatom=massofatomatomicmass

To determine: The amount (moles) of compound in 1.00g of Na2HPO4 .

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