A 0.755-g sample of hydrated copper(II) sulfate CuSo 4 ⋅ x H 2 O was heated carefully until it had changed completely to anhydrous copper(II) sulfate (CuSO 4 ) with a mass of 0.4183 g. Determine the value of x. [This number is called the number of waters of hydration of copper(II) sulfate. It specifies the number of water molecules per formula unit ofCuSO 4 in the hydrated crystal.]

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Interpretation Introduction Interpretation: A 0.755 g sample of hydrated copper (II) sulfate ( CuSO 4 ⋅ x H 2 O ) is given. It is heated till it gets converted to anhydrous copper (II) sulfate. The value of x is to be calculated. Concept introduction: The number of moles of a substance is calculated by the formula, Number of moles = Given mass of the substance Molar mass of the substance To determine: The value of x in CuSO 4 ⋅ x H 2 O . Explanation Given The mass of CuSO 4 ⋅ x H 2 O is 0.755 g . The mass of CuSO 4 is 0.483 g . The mass of water can be calculated by the formula, Mass of water = Mass of CuSO 4 ⋅ x H 2 O − Mass of CuSO 4 Substitute the value of the mass of CuSO 4 ⋅ x H 2 O and the mass of CuSO 4 in the above expression. Mass of water = ( 0.755 − 0.483 ) g =0 .272 g The molar mass of H 2 O = 2 H + O = ( ( 2 × 1 ) + 16 ) g / mol = 18 g / mol The molar mass of CuSO 4 = Cu + S + 4 O = ( 63.5 + 32 + ( 4 × 16 ) ) g / mol = 159.5 g / mol Formula The number of moles of a substance is calculated by the formula, Number of moles = Given mass of the substance Molar mass of the substance Substitute the value of the given mass and the molar mass of water and CuSO 4 in the above expression

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Publisher: Cengage Learning

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Interpretation Introduction

Interpretation: A 0.755 g sample of hydrated copper (II) sulfate (CuSO4⋅xH2O) is given. It is heated till it gets converted to anhydrous copper (II) sulfate. The value of x is to be calculated.

Concept introduction: The number of moles of a substance is calculated by the formula,

Number of moles=Given mass of the substanceMolar mass of the substance

To determine: The value of x in CuSO4⋅xH2O .

Explanation of Solution

Given

The mass of CuSO4⋅xH2O is 0.755 g .

The mass of CuSO4 is 0.483 g .

The mass of water can be calculated by the formula,

Mass of water=Mass of CuSO4⋅xH2O−Mass of CuSO4

Substitute the value of the mass of CuSO4⋅xH2O and the mass of CuSO4 in the above expression.

Mass of water=(0.755−0.483) g=0.272 g

The molar mass of H2O =2H+O=((2×1)+16) g/mol=18 g/mol

The molar mass of CuSO4 =Cu+S+4O=(63.5+32+(4×16)) g/mol=159.5 g/mol

Formula

The number of moles of a substance is calculated by the formula,

Number of moles=Given mass of the substanceMolar mass of the substance

Substitute the value of the given mass and the molar mass of water and CuSO4 in the above expression

Chemistry: An Atoms First Approach

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Chemistry: An Atoms First Approach

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