   Chapter 9.4, Problem 48E ### Mathematical Applications for the ...

11th Edition
Ronald J. Harshbarger + 1 other
ISBN: 9781305108042

#### Solutions

Chapter
Section ### Mathematical Applications for the ...

11th Edition
Ronald J. Harshbarger + 1 other
ISBN: 9781305108042
Textbook Problem

# Revenue The total revenue, in dollars, for a commodity is described by the function R = 300 x − 0.02 x 2 (a) What is the marginal revenue when 40 units are sold?(b) Interpret your answer to part (a).

(a)

To determine

To calculate: The marginal revenue, in dollars for R(x)=300x0.02x2 when 40 units are sold.

Explanation

Given Information:

The provided revenue function is R(x)=300x0.02x2.

Formula Used:

The marginal revenue for a function R(x) is given by R(x).

According to sum rule of derivatives,

If

f(x)=u(x)+v(x)

Then,

f(x)=u(x)+v(x)

According to power rule,

If f(x)=xn, then f(x)=nxn1.

Coefficient rule for a constant c is such that, if f(x)=cu(x), where u(x) is a differentiable function of x, then f(x)=cu(x).

Calculation:

Consider the provided revenue function is R(x)=300x0.02x2.

The marginal revenue for a function R(x) is given by R(x)

(b)

To determine

The interpretation from marginal revenue, in dollars for R(x)=300x0.02x2 when 40 units are sold.

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