   # Calculate ∆S surr for the following reactions at 25°C and 1 atm. a. C 3 H 8 ( g ) + 5O 2 ( g ) → 3CO 2 ( g ) + 4H 2 O( l ) ∆H ° = −2221 kJ b. 2NO 2 ( g ) → 2NO( g ) + O 2 ( g ) ∆H ° = 112 kJ ### Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781305079243

#### Solutions

Chapter
Section ### Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781305079243
Chapter 16, Problem 34E
Textbook Problem
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## Calculate ∆Ssurr for the following reactions at 25°C and 1 atm.a. C3H8(g) + 5O2(g) → 3CO2(g) + 4H2O(l) ∆H° = −2221 kJb. 2NO2(g) → 2NO(g) + O2(g) ∆H° = 112 kJ

(a)

Interpretation Introduction

Interpretation: The values of ΔH , temperature and pressure for the stated reactions are given. The value of ΔSsurr is to be calculated in each case.

Concept introduction: Entropy is the measure of degree of disorder or randomness. Entropy of surrounding (ΔSsurr) decreases for endothermic process whereas, it increases for exothermic process.

### Explanation of Solution

Given

Temperature is 25°C .

The stated reaction is,

C3H8(g)+5O2(g)3CO2(g)+4H2O(l)

The value of ΔH for this reaction is 2221kJ .

The conversion of degree Celsius (°C) into Kelvin (K) is done as,

T(K)=T(°C)+273

Hence,

The conversion of 25°C into Kelvin is,

T(K)=T(°C)+273T(K)=

(b)

Interpretation Introduction

Interpretation: The values of ΔH , temperature and pressure for the stated reactions are given. The value of ΔSsurr is to be calculated in each case.

Concept introduction: Entropy is the measure of degree of disorder or randomness. Entropy of surrounding (ΔSsurr) decreases for endothermic process whereas, it increases for exothermic process.

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