   # Carbon tetrachloride (CCl 4 ) and benzene (C 6 H 6 ) form ideal solutions. Consider an equimolar solution of CCl 4 and C 6 H 6 at 25°C. The vapor above the solution is collected and condensed. Using the following data, determine the composition in mole fraction of the condensed vapor. Substance Δ G f o C 6 H 6 ( l ) 124.50 kJ/mol C 6 H 6 ( g ) 129.66 kJ/mol CCI 4 ( l ) −65.21 kJ/mol CCI 4 ,( g ) −60.59 kJ/mol ### Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781305079243

#### Solutions

Chapter
Section ### Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781305079243
Chapter 16, Problem 114CP
Textbook Problem
311 views

## Carbon tetrachloride (CCl4) and benzene (C6H6) form ideal solutions. Consider an equimolar solution of CCl4 and C6H6 at 25°C. The vapor above the solution is collected and condensed. Using the following data, determine the composition in mole fraction of the condensed vapor. Substance Δ G f o C6H6(l) 124.50 kJ/mol C6H6(g) 129.66 kJ/mol CCI4(l) −65.21 kJ/mol CCI4,(g) −60.59 kJ/mol

Interpretation Introduction

Interpretation: The composition of benzene (C6H6) and carbon tetrachloride (CCl4) in mole fraction of the condensed vapor is to be calculated by using the given data.

Concept introduction: Equilibrium constant K , is the measure of concentration of reactants and products of a system at equilibrium. If the reaction is at equilibrium and the equilibrium is expressed as partial pressure (P) , then the free energy change is,

ΔG=0Q=P

ΔG°=RTln(P)

The expression for standard Gibbs free energy, ΔG° , is,

ΔG°=npΔG°(product)nfΔG°(reactant)

### Explanation of Solution

The reaction that takes place for benzene is,

C6H6(l)C6H6(g)

The reaction that takes place for carbon tetrachloride is,

CCl4(l)CCl4(g)

Given table,

The value of ΔG°(kJ/mol) for the given reactant and product is,

 Molecules ΔG°(kJ/mol) C6H6(l) 124.50 C6H6(g) 129.66 CCl4(l) −65.21 CCl4(g) −60.59

The formula of ΔG° is,

ΔG°=npΔG°(product)nfΔG°(reactant) (1)

Where,

• np is the number of moles of each product.
• nr is the number of moles each reactant.
• ΔG°(product) is the free energy of product at a pressure of 1atm .
• ΔG°(reactant) is the free energy of reactant at a pressure of 1atm .

Substitute all the values from the table for C6H6 in the above equation.

ΔG°=npΔG°(product)nfΔG°(reactant)=[1(129.66)1(124.50)]kJ/mol=5.61kJ/mol_

Substitute all the values from the table for CCl4 in equation (1).

ΔG°=npΔG°(product)nfΔG°(reactant)=[1(60.59)1(65.21)]kJ/mol=4.62kJ/mol_

The value of ΔG°  for benzene is 5.61kJ/mol .

Temperature is 298K .

The conversion of kilo-joule (kJ) into joule (J) is done as,

1kJ=103J

Hence,

The conversion of 5.61kJ into joule is,

5.61kJ=(5.61×103)J=5.61×103J

Formula

ΔG=ΔG°+RTln(Q)

Where,

• ΔG is the free energy change for a reaction at specified pressure.
• R is the gas law constant (8.3145J/Kmol) .
• T is the absolute temperature.
• Q is the reaction constant.

Since, the reaction is at equilibrium, the free energy change,

ΔG=0Q=P1

Where,

P1 is the partial pressure of benzene

### Still sussing out bartleby?

Check out a sample textbook solution.

See a sample solution

#### The Solution to Your Study Problems

Bartleby provides explanations to thousands of textbook problems written by our experts, many with advanced degrees!

Get Started

Find more solutions based on key concepts
Describe diffusion in terms or entropy.

Biology: The Unity and Diversity of Life (MindTap Course List)

People most often choose foods for the nutrients they provide. T F

Nutrition: Concepts and Controversies - Standalone book (MindTap Course List)

23. Name each compound:

Chemistry In Focus

Describe two ways an atom can become excited.

Horizons: Exploring the Universe (MindTap Course List)

In the following diagram, designate each daughter cell as diploid (2n) or haploid (n).

Human Heredity: Principles and Issues (MindTap Course List)

A passenger sitting in the rear of a bus claims that she was injured when the driver slammed on the brakes, cau...

Physics for Scientists and Engineers, Technology Update (No access codes included) 