   Chapter 19, Problem 74GQ

Chapter
Section
Textbook Problem

A current of 0.0100 A is passed through a solution of rhodium sulfate, causing reduction of the metal ion to the metal. After 3.00 hours, 0.038 g of Rh has been deposited. What is the charge on the rhodium ion, Rhn+? What is the formula for rhodium sulfate?

Interpretation Introduction

Interpretation:

The charge of Rhodium ion and formula for rhodium sulphate has to be determined.

Concept introduction:

Electrolysis:

It is a decomposition of ionic compounds by passing electricity through molten compounds or aqueous solutions of compounds.

Electricity used to produce chemical changes. The apparatus used for electrolysis is called an electrolytic cell.

Current:

Rate of the charge changing in time.

The formula is as follows.

Current (Amperes, A) = Electric charge (Coloumbs, C)time, t(seconds,s)

Simplify as follows.

Current = Electric charge time

To rearrange the above formula is as follows.

Charge = Current(A) × time(s)

Explanation

Let’s calculate the charge passing through the cell.

Charge(C)= Current (A) × time (s)= 3.0×104 A × 24 h × (60 min h-1)(60 s min-1)= 108 C

Let’s calculate the moles electrons:

1mol e = (108 C)(1 mol e96500 C)= 1.119×103 mol e-

Let’s calculate the number of moles of Rhodium.

1.119×10-3 m = (0

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