   Chapter 19, Problem 11PS

Chapter
Section
Textbook Problem

For each of the following electrochemical cells, write equations for the oxidation and reduction half-reactions and for the overall reaction. (a) Cu(s)|Cu2+(aq)||Fe3+(aq), Fe2+(aq)|Pt(s) (b) Pb(s)|PbSO4(s)|SO42−(aq)||Fe3+(aq), Fe2+(aq)|Pt(s)

a)

Interpretation Introduction

Interpretation:

The equation for the oxidation and reduction half reactions for the given electrochemical cell has to be determined.

1. a) Cu(s)| Cu2+(aq) || Fe3+(aq),Fe2+(aq)|  Pt(s)

Concept introduction:

Electrochemical cells:

Therese are chemical energy is converted into electrical energy.

In all electrochemical cells , oxidation occurs at anode and reduction occurs at cathode.

An anode is indicated by negative sign and cathode is indicated by the positive sign.

Electrons flow in the external circuit from the anode to the cathode.

In the electrochemical cells two half cells are connected with salt bridge. It allows the cations and anions to move between the two half cells.

Explanation

The given electrochemical cell is as fllows.

Cu(s)| Cu2+(aq) || Fe3+(aq),Fe2+(aq)|  Pt(s)

Oxidation half cell:

Cu(s) Cu2+(aq) + 2e-

Reduction half cell:

Fe+3(aq)+e- Fe+2(aq)

Overall reaction is as follows

b)

Interpretation Introduction

Interpretation:

The equation for the oxidation and reduction half reactions for the given electrochemical cell has to be determined.

Pb(s)| PbSO4(s) | SO42-(aq) || Fe3+(aq) , Fe2+(aq) | Pt(s)

Concept introduction:

Electrochemical cells:

Therese are chemical energy is converted into electrical energy.

In all electrochemical cells , oxidation occurs at anode and reduction occurs at cathode.

An anode is indicated by negative sign and cathode is indicated by the positive sign.

Electrons flow in the external circuit from the anode to the cathode.

In the electrochemical cells two half cells are connected with salt bridge. It allows the cations and anions to move between the two half cells.

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