Chapter 19, Problem 75GQ

### Chemistry & Chemical Reactivity

10th Edition
John C. Kotz + 3 others
ISBN: 9781337399074

Chapter
Section

### Chemistry & Chemical Reactivity

10th Edition
John C. Kotz + 3 others
ISBN: 9781337399074
Textbook Problem

# A current of 0.44 A is passed through a solution of ruthenium nitrate causing reduction of the metal ion to the metal. After 25.0 minutes, 0.345 g of Ru has been deposited. What is the charge on the ruthenium ion, Run+? What is the formula for ruthenium nitrate?

Interpretation Introduction

Interpretation:

The charge of Ruthenium ion and formula for Ruthenium nitrate has to be determined.

Concept introduction:

Electrolysis:

It is a decomposition of ionic compounds by passing electricity through molten compounds or aqueous solutions of compounds.

Electricity used to produce chemical changes. The apparatus used for electrolysis is called an electrolytic cell.

Current:

Rate of the charge changing in time.

The formula is as follows.

Current (Amperes, A) = Electric charge (Coloumbs, C)time, t(seconds,s)

Simplify as follows.

Current = Electric charge time

To rearrange the above formula is as follows.

Charge = Current(A) × time(s)

Explanation

Letâ€™s calculate the charge passing through the cell.

Charge(C)=Â CurrentÂ (A)Â Ã—Â timeÂ (s)=Â 0.44Â AÂ Ã—Â 25Â minÂ (60Â sÂ min-1)=Â 660Â C

Letâ€™s calculate the moles electrons:

1molÂ eâˆ’Â =Â (660Â C)(1Â molÂ eâˆ’96500Â C)=Â 6.839Ã—10âˆ’3Â molÂ e-

Letâ€™s calculate the number of moles of Rhodium.

6.839Ã—10-3Â molÂ eâˆ’Â =Â (0

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