General, Organic, and Biological Chemistry - 4th edition
General, Organic, and Biological Chemistry - 4th edition
4th Edition
ISBN: 9781259883989
Author: by Janice Smith
Publisher: McGraw-Hill Education
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Chapter 20, Problem 58P
Interpretation Introduction

(a)

Interpretation:

The acetal and hemiacetal in sophorose needs to be labeled.

Concept Introduction:

In a hemiacetal, an alcohol and ether attached to the same carbon.

A hemiacetal with an alcohol forms an acetal.

  General, Organic, and Biological Chemistry - 4th edition, Chapter 20, Problem 58P

Interpretation Introduction

(b)

Interpretation:

Each monosaccharide ring should be numbered.

Concept Introduction:

Monosaccharides or simple sugars are the simplest carbohydrates. Generally, have three to six carbon atoms in achain, with a carbonyl group at either the terminal carbon, numbered C1, or the carbon adjacent to it, numbered C2.

Interpretation Introduction

(c)

Interpretation:

Glycosidic linkage needs to be classified as a or β and its location should be designated using numbers.

Concept Introduction:

Disaccharides are carbohydrates composed of two monosaccharides.

Disaccharides are acetals, compounds that contain two alkoxy groups (OR groups) bonded to the same carbon.

A disaccharide results when a hemiacetal of one monosaccharide reacts with a hydroxyl group of a second monosaccharide to form an acetal. The new C-O bond that joins the two rings together is called a glycosidic linkage.

The two monosaccharide rings may be five-membered or six-membered. All disaccharides contain at least one acetal that joins the rings together. Each ring is numbered beginning at the anomeric carbon, the carbon in each ring bonded to two oxygen atoms

An a glycoside has the glycosidic linkage oriented down, below the plane of the ring that

contains the acetal joining the monosaccharides.

A β glycoside has the glycosidic linkage oriented up, above the plane of the ring that

contains the acetal joining the monosaccharides.

Interpretation Introduction

(d)

Interpretation:

Whether the hemiacetal drawn as an a or β anomer should be predicted.

Concept Introduction:

Anomers are cyclic monosaccharides or glycosides that are epimers, differing from each other in the configuration of C-1 if they are aldoses or in the configuration at C-2 if they are ketoses. The epimeric carbon in anomers are known as anomeric carbon or anomeric center.

Depending on the orientation of carbon number 1 when the carbon number 5 hydroxyl bonds to it, two different forms can result.

These two forms are identical except for the configuration around C1. These two forms are called anomers.

C1 is called the anomeric carbon. If the hydroxyl group on C1 and the -CH2OH group on C5 are on opposite sides of the six-membered ring, C1 is known to be the a anomer.

If they are on the same side, C1 is known to be the β anomer.

Interpretation Introduction

(e)

Interpretation:

The monosaccharide formed when sophorose is hydrolyzed needs to be determined.

Concept Introduction:

Disaccharides are carbohydrates composed of two monosaccharides.

Disaccharides are acetals, compounds that contain two alkoxy groups (OR groups) bonded to the same carbon.

A disaccharide results when a hemiacetal of one monosaccharide reacts with a hydroxyl group of a second monosaccharide to form an acetal. The new C-O bond that joins the two rings together is called a glycosidic linkage.

The two monosaccharide rings may be five-membered or six-membered. All disaccharides contain at least one acetal that joins the rings together. Each ring is numbered beginning at the anomeric carbon, the carbon in each ring bonded to two oxygen atoms.

The hydrolysis of a disaccharide cleaves the C-O glycosidic linkage and forms two monosaccharides.

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Chapter 20 Solutions

General, Organic, and Biological Chemistry - 4th edition

Ch. 20.3 - Prob. 20.3PPCh. 20.3 - Prob. 20.4PPCh. 20.4 - Prob. 20.5PPCh. 20.4 - Prob. 20.6PPCh. 20.4 - Prob. 20.9PCh. 20.4 - Prob. 20.10PCh. 20.5 - Prob. 20.7PPCh. 20.5 - Prob. 20.8PPCh. 20.5 - Lactose contains both an acetal and a hemiacetal....Ch. 20.5 - Prob. 20.12PCh. 20.5 - Prob. 20.13PCh. 20.5 - Prob. 20.14PCh. 20.5 - Prob. 20.15PCh. 20.6 - Prob. 20.16PCh. 20.6 - Prob. 20.17PCh. 20.7 - Prob. 20.18PCh. 20.7 - Prob. 20.19PCh. 20.8 - Prob. 20.20PCh. 20 - Prob. 21PCh. 20 - Prob. 22PCh. 20 - Prob. 23PCh. 20 - Prob. 24PCh. 20 - Prob. 25PCh. 20 - Prob. 26PCh. 20 - Prob. 27PCh. 20 - Prob. 28PCh. 20 - Prob. 29PCh. 20 - Prob. 30PCh. 20 - Prob. 31PCh. 20 - Prob. 32PCh. 20 - Prob. 33PCh. 20 - Prob. 34PCh. 20 - Prob. 35PCh. 20 - Prob. 36PCh. 20 - Prob. 37PCh. 20 - Prob. 38PCh. 20 - Prob. 39PCh. 20 - Prob. 40PCh. 20 - Prob. 41PCh. 20 - Prob. 42PCh. 20 - Prob. 43PCh. 20 - Prob. 44PCh. 20 - Prob. 45PCh. 20 - Prob. 46PCh. 20 - What product is formed when each compound is...Ch. 20 - What product is formed when each compound is...Ch. 20 - Prob. 49PCh. 20 - Prob. 50PCh. 20 - Prob. 51PCh. 20 - Prob. 52PCh. 20 - Prob. 53PCh. 20 - Prob. 54PCh. 20 - Prob. 55PCh. 20 - Prob. 56PCh. 20 - Prob. 57PCh. 20 - Prob. 58PCh. 20 - Prob. 59PCh. 20 - Prob. 60PCh. 20 - Prob. 61PCh. 20 - Prob. 62PCh. 20 - Prob. 63PCh. 20 - Prob. 64PCh. 20 - Prob. 65PCh. 20 - Prob. 66PCh. 20 - Prob. 67PCh. 20 - Prob. 68PCh. 20 - Prob. 69PCh. 20 - Prob. 70PCh. 20 - Prob. 71PCh. 20 - Prob. 72PCh. 20 - Prob. 73PCh. 20 - Prob. 74PCh. 20 - Prob. 75PCh. 20 - Prob. 76PCh. 20 - Prob. 77PCh. 20 - Prob. 78PCh. 20 - Prob. 79CPCh. 20 - Prob. 80CP
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