Genetics: Analysis and Principles
Genetics: Analysis and Principles
6th Edition
ISBN: 9781259616020
Author: Robert J. Brooker Professor Dr.
Publisher: McGraw-Hill Education
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Chapter 24, Problem 9EQ
Summary Introduction

To review:

The working of the BACKTRANSLATE program, its genetic principle, and the sequence generated by this program.

Introduction:

Amino acids are the organic compounds that form proteins, which are the building blocks of the body. An amino acid contains carboxyl and amine functional groups and also has a side chain which is particular for each amino acid. The chain of amino acids is made according to the base sequence of mRNA (messenger ribonucleic acid).

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A researcher sequences the genome of a variety of bacterial and eukaryotic cells. She finds that the bacterial genome is smaller, but that there are more genes for a given number of base pairs in the eukaryotic cells. In other words, there are fewer genes per unit of length of DNA in the eukaryotic cells. What do you predict she will find if she examines the DNA more closely? A. All of the bacterial DNA consists of coding sequences, but this is not true of the eukaryotic DNA. B. There are more repetitive sequences in the eukaryotic DNA than in the bacterial DNA. C. There are densely packed genes in the eukaryotic DNA that were not immediately distinguishable during the first analysis. D. The bacteria have larger quantities of noncoding DNA than the eukaryotic cells.
Which one of the following options would be a good way to identify the location of the poly A tail in the published DNA sequence for a gene? Look for AATAAA near the 3’ UTR of the DNA sequence. Look for TTTTTTTTTTTTTT… (many Ts) near the 3’ UTR of the DNA sequence. Look for AAAAAAAAAAA… (many As) near the 3’ UTR of the DNA sequence. Look for a stop codon.
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