   # The compound As 2 I 4 is synthesized by reaction of arsenic metal with arsenic triiodide. If a solid cubic block of arsenic ( d = 5.72 g/cm 3 ) that is 3.00 cm on edge is allowed to react with 1.01 × 10 24 molecules of arsenic triiodide, what mass of As 2 I 4 can be prepared? If the percent yield of As 2 I 4 was 75.6%, what mass of As 2 I 4 was actually isolated? ### Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781305079243

#### Solutions

Chapter
Section ### Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781305079243
Chapter 5, Problem 182IP
Textbook Problem
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## The compound As2I4 is synthesized by reaction of arsenic metal with arsenic triiodide. If a solid cubic block of arsenic (d = 5.72 g/cm3) that is 3.00 cm on edge is allowed to react with 1.01 × 1024 molecules of arsenic triiodide, what mass of As2I4 can be prepared? If the percent yield of As2I4 was 75.6%, what mass of As2I4 was actually isolated?

Interpretation Introduction

Interpretation: The mass of As2I4 that can be prepared and the mass of As2I4 actually isolated is to be calculated.

Concept introduction: The number of moles is defined as the ratio of mass with the molecular mass of an element. The mass of an element is the amount of the substance present in an element. The mass is calculated by using number of moles in an element.

To determine: The mass of As2I4 that can be prepared and the mass of As2I4 actually isolated.

### Explanation of Solution

Explanation

Given

Density of block of arsenic is 5.72 g/cm3 .

Edge of block is 3.00 cm .

Molecules of arsenic triiodide are 1.01×1024 molecules.

Percent yield of As2I4 is 75.6% .

Molecular mass of arsenic is 74.92 g/mol .

The reaction between As block and AsI3 is,

2As+4AsI33AsI4

The volume of block is given by the formula,

Volume of cubical block=(side)3 .

Substitute the value of given edge in the above expression to calculate the volume of block.

Volume of cubical block=(side)3=(3 cm)3=27 cm3

The mass of arsenic is calculated by using the expression,

Mass=density×volume .

Substitute the value of density and volume in the above expression,

Mass=density×volume=5.72 g/cm3×27 cm3=154.44 g

Now, the number of moles of arsenic is calculated by using the expression,

Number of moles=MassMolar mass

Substitute the value of mass and molar mass of arsenic in the above expression,

Number of moles=MassMolar mass=154.44 g74.92 g/mol=2.061 mol

Now, 1 mole contains Avogadro’s number of particles, the number of moles of AsI3 is calculated as,

Number of moles of AsI3=Number of molecules of AsI3NA .

Where,

• NA=6.022×1023 is the Avogadro’s number.

Substitute the value of number of molecules and NA in the above expression to calculate the number of moles of AsI3 .

Number of moles of AsI3=Number of molecules of AsI3NA=1

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