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Chemistry & Chemical Reactivity

10th Edition
John C. Kotz + 3 others
ISBN: 9781337399074

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Chapter
Section
BuyFindarrow_forward

Chemistry & Chemical Reactivity

10th Edition
John C. Kotz + 3 others
ISBN: 9781337399074
Textbook Problem

As a gas cools, it is compressed from 2.50 L to 1.25 L under a constant pressure of 1.01 × 105 Pa. Calculate the work (in J) required to compress the gas.

Interpretation Introduction

Interpretation:

The work done under the compression of a gas has to be determined.

Concept Introduction:

The amount of work done to the system or from the system is

  W=-P(ΔV)

Where,

  ΔV is the change in volume

   P is the pressure.

Explanation

Given,

  Initial volume =2.50L

  Final volume=1.25L

  Pressure=1.01×105P

Work done at constant pressure, Wp=-PΔV

Substitute in above equation as,Wp=-1.01×105kg/ms2(1.25L-2

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