   Chapter 5, Problem 32PS

Chapter
Section
Textbook Problem

Nitrogen gas is confined in a cylinder with a movable piston under a constant pressure of 9.95 × 104 Pa. When 695 J of energy in the form of heat is transferred from the gas to the surroundings, its volume decreases by 1.88 L. What is the change in internal energy of the gas?

Interpretation Introduction

Interpretation:

The change in internal energy under the compression of nitrogen gas has to be determined.

Concept Introduction:

The internal energy, U is the sum of kinetic energy and the potential energy inside the system.

Change in internal energy,ΔU, is the measures of energy that is transferred as heat and work from the system or to the system.

ΔU=qp+Wp

Where q = heat energy absorbed or released, W =work done to the system or from the system.

W=-P(ΔV) ,

Where,

ΔV is the change in volume, and P is the pressure.

Explanation

Given,

ΔV=1.88L

qp=-695J(heat is transferred from the system)

Pressure=9.95×104P

Work done at constant pressure, Wp=-PΔV

Substitute in above equation as,

Wp=-9.95×104kg/ms2(-1.88L)Wp=-9.95×104kg/ms2(-1.88m3)Wp=-9.95×104kg/ms2(-1

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