   Chapter 5, Problem 39PS

Chapter
Section
Textbook Problem

A piece of titanium metal with a mass of 20.8 g is heated in boiling water to 99.5 °C and then dropped into a coffee-cup calorimeter containing 75.0 g of water at 21.7 °C. When thermal equilibrium is reached, the final temperature is 24.3 °C. Calculate the specific heat capacity of titanium.

Interpretation Introduction

Interpretation:

The specific heat capacity of titanium has to be calculated.

Concept Introduction:

Heat energy required to raise the temperature of 1g of substance by 1K.Energy gained or lost can be calculated using the below equation.

q=C×m×ΔT

Where, q= energy gained or lost for a given mass of substance (m), C =specific heat

Capacity,ΔT= change in temperature.

Explanation

Assume qmetal=-qwater

20.8g×Cmetal(24.3K-99.5K)=-[75g×4.184J/gK(24

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