Chapter 5, Problem 87GQ

### Chemistry & Chemical Reactivity

10th Edition
John C. Kotz + 3 others
ISBN: 9781337399074

Chapter
Section

### Chemistry & Chemical Reactivity

10th Edition
John C. Kotz + 3 others
ISBN: 9781337399074
Textbook Problem

# (a) Calculate the enthalpy change, ΔrH°, for the formation of 1.00 mol of strontium carbonate (the material that gives the red color in fire­works) from its elements. Sr(s) + C(s) + 3 2 , O2(g) → SrCO3(s)The experimental information available isSr(s) +½ O2(g) → SrO(s)       ΔfH° = –592 kJ/mol-rxnSrO(s) + CO2(g) → SrCO3(s)       ΔrH° = –234 kJ/mol-rxnC(graphite) + O2(g) → CO2(g)       ΔfH° = –394 kJ/mol-rxn (b) Draw an energy level diagram relating the energy quantities in this problem.

(a)

Interpretation Introduction

Interpretation:

The enthalpy change of formation of 1mol of SrCO3 has to be determined

Concept Introduction:

The standard enthalpy change of combustion of a compound is the enthalpy change which occurs when one gram of the compound is burned completely in oxygen under standard conditions, and with everything in its standard state.

ΔrH0=ΣnΔfH0(products)-ΣnΔfH0(reactants)

Explanation

Adding all the equations given, the required equation is observed. Therefore adding 3Î”fH0 of the corresponding equation we get,

Given formation constant are:

â€‚Â 1.â€‰Î”rH0=â€‰-592â€‰kJ/mol2.â€‰Î”rH0=â€‰-234â€‰kJ/mol3

(b)

Interpretation Introduction

Interpretation:

The energy level diagram for the change of formation of 1mol of SrCO3 has to be depicted.

Concept Introduction:

The standard enthalpy change of combustion of a compound is the enthalpy change which occurs when one gram of the compound is burned completely in oxygen under standard conditions, and with everything in its standard state.

ΔrH0=ΣnΔfH0(products)-ΣnΔfH0(reactants)

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