Biochemistry: The Molecular Basis of Life
Biochemistry: The Molecular Basis of Life
6th Edition
ISBN: 9780190209896
Author: Trudy McKee, James R. McKee
Publisher: Oxford University Press
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Chapter 6, Problem 16RQ
Summary Introduction

To review:

The reason for the stability of glucose (C6 H12O6) in an oxygen atmosphere for appreciable periods of time if the change in enthalpy (ΔH) for the given reaction is –28.2 kJ/mol (kilo Joule per mole).

C6H12O6+ 6O26CO2+ 6H2O

Introduction:

Enthalpy of a reaction can be defined as the amount of heat absorbed or evolved in a reaction that is carried out at a constant pressure. It is given by the symbol ΔH.It is the sum of Gibbs’ free energy (G) of the system and the product of entropy change(ΔS) and temperature (T). It can be given by the equation: ΔH=ΔG+TΔS.

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The conversion of glucose-1-phosphate to glucose-6-phosphate by the enzyme phosphoglucomutase has a △G°' of -7.6 kJ/mol. Calculate the equilibrium constant for this reaction at 298 K and a pH of 7. (R = 8.315 J/K-mol)   A. 0.003   B. 0.047   C. 1.00   D. 21
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Chapter 6 Solutions

Biochemistry: The Molecular Basis of Life

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