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(a)
Interpretation:
Among the given compounds, the one that is soluble in hydrocarbon solvents is to be identified.
Concept introduction:
A compound is said to be a polar due to the presence of an electronegative atom that tends to attract the electrons closer to itself as compared to the other atom. The electronegative atom acquires a partial negative charge and creates a partial positive charge on the other atom. Polar compounds are soluble in polar solvents, whereas non-polar compounds are soluble in non-polar solvents.
(b)
Interpretation:
Among the given compounds, the one that would be present in greater amount in a hexane solution as separately solvated ions, or ion pairs and higher aggregates is to be identified.
Concept introduction:
A compound is said to be a polar due to the presence of an electronegative atom that tends to attract the electrons closer to itself as compared to the other atom. The electronegative atom acquires a partial negative charge and creates a partial positive charge on the other atom. Polar compounds are soluble in polar solvents, whereas non-polar compounds are soluble in non-polar solvents.
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Chapter 8 Solutions
EBK ORGANIC CHEMISTRY
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- 6. (a) Aspirin is a weak acid with a pKa of 3.6 and MW 180 g/mol. The saturation solubility (S) of aspirin in water is 3.3 g /L and a saturated solution has pH equal to your answer to question 4(b) above. What is the solubility of the unionised form (So) of aspirin at this pH using units of mol/L and g/L. (b) Use the So value (just obtained) to calculate the saturation solubility (S) of aspirin in water at pH 6.6 using units of mol/L and g/L. (c) If you modified the aspirin suspension APF12 formula by replacing the purified water with pH 6.6 buffer, would the product be a suspension or solution?arrow_forwardIf the temperature is increased in a saturated solution of A in equilibrium with solid A, what will you observe? Give a thermodynamic explanation for this (based on chemical potential and mole fraction)arrow_forwardThe following reaction scheme is given: Aluminum metal added to a strong base aqueous solution provides a colorless solution (A), releasing a colorless gas (B). Introduction of carbon dioxide gas into (A) precipitates a white gelatinous precipitate (C). (C) is divided into two equal parts. To one portion, excess sodium hydroxide solution is added, dissolving the precipitate to a colorless solution (D). By annealing the other part of (C) at high temperature, an anhydrous white oxide (E) is formed. Write the corresponding equilibrium chemical equations for the described reactions and name the chemical forms (A) to (E).arrow_forward
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- Principles of Modern ChemistryChemistryISBN:9781305079113Author:David W. Oxtoby, H. Pat Gillis, Laurie J. ButlerPublisher:Cengage LearningOrganic Chemistry: A Guided InquiryChemistryISBN:9780618974122Author:Andrei StraumanisPublisher:Cengage Learning
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