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Genetics: From Genes to Genomes, 5th edition
5th Edition
ISBN: 9780073525310
Author: Leland H. Hartwell, Michael L. Goldberg, Janice A. Fischer, Leroy Hood, Charles F. Aquadro
Publisher: McGraw-Hill Education
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Textbook Question
Chapter 15, Problem 13P
For each of the following mutant E. coli strains, plot a 30-minute time course of concentration of β-galactosidase, permease, and acetylase enzymes grown under the following conditions: For the first 10 minutes, no lactose is present; at 10ˊ lactose becomes the sole carbon source. Plot concentration on the y-axis, time on the x-axis. (Don’t worry about the exact units for each protein on the y-axis.)
a. | I-P+o+Z+Y+A+/ I+P+o+Z-Y+A+ |
b. | I-P+ocZ+Y+A+/ I+P+o+Z-Y+A+ |
c. | IsP+o+Z+Y+A+/ I-P+o+Z-Y+A+ |
d. | I-P-o+Z+Y+A+/ I-P+ocZ+Y-A+ |
e. | I-P+o+Z-Y+A+/ I-P-ocZ+Y-A+ |
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Students have asked these similar questions
For E. coli strains with the lac genotypes show below, use a plus sign (+) to indicate the synthesis of β-galactosidase and permease and a minus sign (–) to indicate no synthesis of the proteins.
For each of the following genotypes, explain how mutation (identified by a (-) will affect the
organism grown in lactose medium. Indicate whether
a) B-galactosidase will be synthesized or not,
b) synthesis of B-galactosidase is inducible (1) or constitutive (C) and
c) growth of the organism will occur or not.
i. I+P+0-Z+Y+A+/l+P+O+Z-Y-A-
ii. I-P+0+Z+Y+A+/I+P-O+Z+Y+A+
Wild-type E. coli cells can synthesize all 20 common amino acids, but some mutants, called amino acid auxotrophs, are unable
to synthesize a specific amino acid and require its addition to the culture medium for optimal growth. Besides their role in
protein synthesis, some amino acids are also precursors for other nitrogenous cell products. Consider the three amino acid
auxotrophs that are unable to synthesize glycine, glutamine, and aspartate, respectively.
Match each nitrogenous product with the mutant or mutants that would fail to synthesize it. Each mutant may fail to synthesize
more than one nitrogenous product, and some nitrogenous products may fail to be synthesized by more than one mutant.
glycine auxotrophs
glutamine auxotrophs
aspartate auxotrophs
Answer Bank
adenine
nucleotides
cytosine
nucleotides
guanine
nucleotides
uridine
nucleotides
Chapter 15 Solutions
Genetics: From Genes to Genomes, 5th edition
Ch. 15 - For each of the terms in the left column, choose...Ch. 15 - The following statement occurs early in this...Ch. 15 - One of the main lessons of this chapter is that...Ch. 15 - All mutations that abolish function of the Rho...Ch. 15 - The promoter of an operon is the site to which RNA...Ch. 15 - You are studying an operon containing three genes...Ch. 15 - Prob. 7PCh. 15 - You have isolated two different mutants reg1 and...Ch. 15 - Bacteriophage , after infecting a cell, can...Ch. 15 - Mutants were isolated in which the constitutive...
Ch. 15 - For each of the E. coli strains containing the lac...Ch. 15 - For each of the growth conditions listed, what...Ch. 15 - For each of the following mutant E. coli strains,...Ch. 15 - Maltose utilization in E. coli requires the...Ch. 15 - Seven E. coli mutants were isolated. The activity...Ch. 15 - Prob. 16PCh. 15 - Six strains of E.coli mutants 16 that had one of...Ch. 15 - a. The original constitutive operator mutations in...Ch. 15 - Prob. 19PCh. 15 - Figure 15.16 on p. 525 shows that in the lac...Ch. 15 - Why is the trp attenuation mechanism unique to...Ch. 15 - a. How many ribosomes are required at a minimum...Ch. 15 - The following is a sequence of the leader region...Ch. 15 - For each of the E. coli strains that follow,...Ch. 15 - One mechanism by which antisense RNAs act as...Ch. 15 - For each element in the list that follows,...Ch. 15 - Great variation exists in the mechanisms by which...Ch. 15 - Many genes whose expression is turned on by DNA...Ch. 15 - Prob. 29PCh. 15 - The E.coli MalT protein is a positive regulator of...Ch. 15 - Prob. 31PCh. 15 - To find genes that are turned on or off in...Ch. 15 - Prob. 33PCh. 15 - Prob. 34PCh. 15 - Prob. 35PCh. 15 - The researchers who investigated bioluminescence...Ch. 15 - Prob. 37PCh. 15 - Quorum sensing controls the expression of...
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- After calculating the extinction coefficient for lysozyme above, you convert it into ml mg cm1 units. (You need not do the calculation, just suppose you did). To calculate the protein concentration in your column fractions (W1-3, E1-2), would your calculated extinction coefficient be a better choice than 1.5 mL mg 1 cm1 value listed in the theory section of your pre-lab? Why or why not? (Choose the best response) Yes, because we expect all of the column fractions to be mainly lysozyme. No, because most, if not all, the column fractions are mixtures of 2 or more proteins. Trick question, we should use the values calculated by EXPASY for lysozyme. Yes, because my calculated value is more accurate than values from the literature. ONo, because lysozyme is still stuck to the column and shouldnot be in any of our column fractions.arrow_forwardIn a mixed heteropolymer experiment, messages were createdwith either 4/5C:1/5A or 4/5A:1/5C. These messages yielded proteinswith the amino acid compositions shown in the followingtable. Using these data, predict the most specific coding compositionfor each amino acid.4/5C:1/5A 4/5A:1/5CPro 63.0% Pro 3.5%His 13.0% His 3.0%Thr 16.0% Thr 16.6%Glu 3.0% Glu 13.0%Asp 3.0% Asp 13.0%Lys 0.5% Lys 50.0% 98.5% 99.1%arrow_forwardFor each of the following genotypes, explain how mutation (identified by a (-) will affect the organism grown in lactose medium. Indicate whether a) B-galactosidase will be synthesized or not, b) synthesis of B-galactosidase is inducible (1) or constitutive (C) and c) growth of the organism will occur or not. a. I-P+O+Z+Y+A+ b. I+P-O+Z+Y+A+ c. I+P+O-Z+Y+A+ d. I+P+0-Z+Y+A+/l+P+O+Z-Y-A- e. I-P+0+Z+Y+A+/l+P-O+Z+Y+A+arrow_forward
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