   # Given the following data: 2 H 2 ( g ) + C ( s ) → CH 4 ( g ) Δ G ∘ = − 51 kJ 2 H 2 ( g ) + O 2 ( g ) → 2 H 2 O ( l ) Δ G ∘ = − 474 kJ C ( s ) + O 2 ( g ) → CO 2 Δ G ∘ = − 394 kJ Calculate ∆G° for CH 4 ( g ) + 2 O 2 ( g ) → CO 2 ( g ) + 2 H 2 O ( l ) . ### Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781305079243

#### Solutions

Chapter
Section ### Chemistry: An Atoms First Approach

2nd Edition
Steven S. Zumdahl + 1 other
Publisher: Cengage Learning
ISBN: 9781305079243
Chapter 16, Problem 57E
Textbook Problem
12 views

## Given the following data: 2 H 2 ( g ) + C ( s ) → CH 4 ( g )           Δ G ∘ = − 51 kJ 2 H 2 ( g ) + O 2 ( g ) → 2 H 2 O ( l )       Δ G ∘ = − 474 kJ C ( s ) + O 2 ( g ) → CO 2       Δ G ∘ = − 394 kJ   Calculate ∆G° for CH 4 ( g ) + 2 O 2 ( g ) → CO 2 ( g ) + 2 H 2 O ( l ) .

Interpretation Introduction

Interpretation: The standard free energy change for the given reaction with the values of standard free energy change of individual reactions is to be calculated.

Concept Introduction: The standard free energy change of the given reaction is the summation of the free energy change of individual reactions.

To determine: The standard free energy change of the given reaction.

### Explanation of Solution

Given

The first individual reaction is,

2H2(g)+C(s)CH4(g)ΔG=51kJ (1)

The second individual reaction is,

2H2(g)+O2(g)2H2O(l)ΔG=474kJ (2)

The third individual reaction is,

C(s)+O2(g)CO2(g)ΔG=394kJ (3)

The reaction with unknown free energy change is,

CH4(g)+2O2(g)CO2(g)+2H2O(l) (4)

Add the equation (2) and (3) and subtract equation (1) from it to get the required reaction

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