Chapter 19, Problem 76GQ

### Chemistry & Chemical Reactivity

10th Edition
John C. Kotz + 3 others
ISBN: 9781337399074

Chapter
Section

### Chemistry & Chemical Reactivity

10th Edition
John C. Kotz + 3 others
ISBN: 9781337399074
Textbook Problem

# The total charge that ran he delivered by a large dry cell battery before its voltage drops too low is usually about 35 amp-hours. (One amp-hour is the charge that passes through a circuit when 1 A flows for 1 hour.) What mass of Zn is consumed when 35 amp-hours are drawn from the cell?

Interpretation Introduction

Interpretation:

The mass of Zinc consumed when 35 amp – hours are drawn from the cell has to be determined.

Concept introduction:

According to the first law of thermodynamics, the change in internal energy of a system is equal ti the heat added to the sysytem minus the work done by the system.

The equation is as follows.

ΔU = Q - WΔU = Change in internal energyQ = Heat added to the systemW=Work done by the system

In voltaic cell, the maximum cell potential is directly related to the free energy difference between the reactants and products in the cell.

ΔG0= -nFE0n = Number of moles transferred per mole of reactant and productsF = Faradayconstant=96485C/mol  E0= Volts = Work(J)/Charge(C)

The relation between standard cell potential and equilibrium constant is as follows.

lnK = nE00.0257 at 298K

The relation between solubility product Ksp and equilibrium constant is as follows.

Ksp= e+lnK

Explanation

Given Amp = 35

ChargeÂ (C)Â =Â CurrentÂ (A)Â Ã—Â timeÂ (s)=35Â AÂ Ã—60Â Ã—60Â s=1.26Ã—105Â C

Letâ€™s calculate the charge of the cell:

Charge(C)Â =Â (moleÂ ofÂ e-)(96500Â C1Â molÂ e-)molÂ ofÂ e-=1.26Ã—105Â C96500Â C=1

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