The henry constant of oxygen at 50 o C to be identified. Concept introduction: Henry’s law: The solubility of a gas in liquid is directly proportional to the gas pressure. S g = k H P g , where, S g is the gas solubility (in mol/kg) k H is Henry's constant P g is the partial pressure of the gaseous solute .

BuyFind

Chemistry & Chemical Reactivity

10th Edition
John C. Kotz + 3 others
Publisher: Cengage Learning
ISBN: 9781337399074
BuyFind

Chemistry & Chemical Reactivity

10th Edition
John C. Kotz + 3 others
Publisher: Cengage Learning
ISBN: 9781337399074

Solutions

Chapter 13, Problem 20PS
Interpretation Introduction

Interpretation: The henry constant of oxygen at 50oC to be identified.

Concept introduction:

Henry’s law: The solubility of a gas in liquid is directly proportional to the gas pressure.

Sg= kHPg,where,Sgisthegassolubility(inmol/kg)kHis Henry's constant Pg is the partial pressure of the gaseous solute.

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