BuyFindarrow_forward

Chemistry & Chemical Reactivity

10th Edition
John C. Kotz + 3 others
ISBN: 9781337399074

Solutions

Chapter
Section
BuyFindarrow_forward

Chemistry & Chemical Reactivity

10th Edition
John C. Kotz + 3 others
ISBN: 9781337399074
Textbook Problem

A solution is 4.00% (by mass) maltose and 96.00% water. It freezes at −0.229 °C.

  1. (a) Calculate the molar mass of maltose (which is not an ionic compound).
  2. (b) The density of the solution is 1.014 g/mL Calculate the osmotic pressure of the solution.

(a)

Interpretation Introduction

Interpretation: The molar mass of maltose solution has to be determined.

Concept introduction:

Colligative properties: Properties of solutions which having influence on the concentration of the solute in it. Colligative properties are,

  • Decrease in the vapor pressure
  • Increase in the boiling point
  • Decline in the freezing point
  • Osmotic pressure

Change in freezing point is calculated by using the equation,

  ΔTfp=Kfpmsolute

  where,

  Kfp is the molal freezing point depression constant.

Osmotic pressure: The pressure created by the column of solution for the system at equilibrium is a measure of the osmotic pressure.

  π=icRT

  where,

  c is the molar concentration

  i is the van’t Hoff factor

The number of moles of any substance can be determined using the equation

  Numberofmole=GivenmassofthesubstanceMolarmass

Density is calculated by the equation,

  Density=massvolume

Molarity (M): Molarity is number of moles of the solute present in the one liter of the solution.

  Molarity (M) =Numberofmolesofsolute1literofsolution

Explanation

Given,

  ΔT=0.2290C

  Mass of maltose is 4g

  Mass of water is 96g=0.096kg

  Molal freezing point depression constant of water is 1.860C/m

Change in freezing point is calculated by using the equation,

  ΔTmp=Kmpmsolute

Hence,

The concentration is calculated by,

  Concentration,msolute=ΔTmpKmp=(0.2290C0C)(1.860C/m)=0

(b)

Interpretation Introduction

Interpretation: The osmotic pressure of the maltose solution has to be determined.

Concept introduction:

Colligative properties: Properties of solutions which having influence on the concentration of the solute in it. Colligative properties are,

  • Decrease in the vapor pressure
  • Increase in the boiling point
  • Decline in the freezing point
  • Osmotic pressure

Osmotic pressure: The pressure created by the column of solution for the system at equilibrium is a measure of the osmotic pressure.

  π=icRT

  where,

  c is the molar concentration

  i is the van’t Hoff factor

The number of moles of any substance can be determined using the equation

  Numberofmole=GivenmassofthesubstanceMolarmass

Density is calculated by the equation,

  Density=massvolume

Molarity (M): Molarity is number of moles of the solute present in the one liter of the solution.

  Molarity (M) =Numberofmolesofsolute1literofsolution

Still sussing out bartleby?

Check out a sample textbook solution.

See a sample solution

The Solution to Your Study Problems

Bartleby provides explanations to thousands of textbook problems written by our experts, many with advanced degrees!

Get Started

Chapter 13 Solutions

Show all chapter solutions add

Additional Science Solutions

Find more solutions based on key concepts

Show solutions add

Under certain circumstances, amino acids can be converted to glucose and so serve the energy needs of the brain...

Nutrition: Concepts and Controversies - Standalone book (MindTap Course List)

On what does the range of a projectile depend?

An Introduction to Physical Science

Why is glucose considered the pivotal compound in carbohydrate metabolism?

Chemistry for Today: General, Organic, and Biochemistry

Energy is to be transmitted over a pair of copper wires in a transmission line at a rate P with only a fraction...

Physics for Scientists and Engineers, Technology Update (No access codes included)