The Practice of Statistics for AP - 4th Edition
The Practice of Statistics for AP - 4th Edition
4th Edition
ISBN: 9781429245593
Author: Starnes, Daren S., Yates, Daniel S., Moore, David S.
Publisher: Macmillan Higher Education
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Chapter 3, Problem 11PT

(a)

To determine

To make: a scatter plot of the givne data.

(a)

Expert Solution
Check Mark

Answer to Problem 11PT

  The Practice of Statistics for AP - 4th Edition, Chapter 3, Problem 11PT , additional homework tip  1

Explanation of Solution

Given:

    Age 36 48 51 54 57 60
    height 86 90 91 93 94 95

Calculation:

The scatter plot for the given data is as follows

  The Practice of Statistics for AP - 4th Edition, Chapter 3, Problem 11PT , additional homework tip  2

From the scatter plot, we can see that all points are showing a linear trend in upward direction. Hence, we can say that there exists a positive correlation between Age and Height. In other words, we can say that Age and Height are positively correlated.

Conclusion:

Hence,scatterplot is drawn.

(b)

To determine

To find: The equation of the least − squares regression line of height on age.

(b)

Expert Solution
Check Mark

Answer to Problem 11PT

The least-square regression line is Height = 71.95+0.0383 Age

Explanation of Solution

Calculation:

Here “age” is the explanatory variable and “height” is the response variable.

Using MINITAB, the output of the least − square regression line is obtained as follows.

Regression Analysis: Height versus Age

  The Practice of Statistics for AP - 4th Edition, Chapter 3, Problem 11PT , additional homework tip  3

From the above output, the least-square regression line is given by

  Height = 71.95+0.0383 Age

Conclusion:

Hence, the least-square regression line is Height = 71.95+0.0383 Age

(c)

To determine

To predict: S’s height at age 40 years

(c)

Expert Solution
Check Mark

Answer to Problem 11PT

S’s height will be 100.7677 inches.

Explanation of Solution

Calculation:

From part (b), the regression line between Age and Height is obtained as

Height = 71.95+0.0383 Age

Using the above regression line, we can predict Sarah’s height at age 40 years (480 months)

That is, the predicted Sarah’s height at age 40 years (480 months) will be,

   Y ^ =71.95+0.383×480=255.94984cm=255.949842.54inches                     (\1 inch = 2.54 cm)= 100.7677 inches = 255.94984 cm= 100.7677 inches

Conclusion:

Hence, the predicted Sarah’s height at age 40 years (480 months) will be 100.7677 inches.

(d)

To determine

To explain: why the prediction is impossibly large.

(d)

Expert Solution
Check Mark

Answer to Problem 11PT

Predicting Sarah’s height at age 40 years (480 months) is an extrapolation of the relationship beyond what the data show.

Explanation of Solution

Age of 40 years (480 months) is far outside the set of X- values for our data. We cannot say whether the relationship remains linear at such extreme values. Predicting Sarah’s height at age 40 years (480 months) is an extrapolation of the relationship beyond what the data show. Hence, we can say that the predicted height is not accurate

Chapter 3 Solutions

The Practice of Statistics for AP - 4th Edition

Ch. 3.1 - Prob. 2ECh. 3.1 - Prob. 3ECh. 3.1 - Prob. 4ECh. 3.1 - Prob. 5ECh. 3.1 - Prob. 6ECh. 3.1 - Prob. 7ECh. 3.1 - Prob. 8ECh. 3.1 - Prob. 9ECh. 3.1 - Prob. 10ECh. 3.1 - Prob. 11ECh. 3.1 - Prob. 12ECh. 3.1 - Prob. 13ECh. 3.1 - Prob. 14ECh. 3.1 - Prob. 15ECh. 3.1 - Prob. 16ECh. 3.1 - Prob. 17ECh. 3.1 - Prob. 18ECh. 3.1 - Prob. 19ECh. 3.1 - Prob. 20ECh. 3.1 - Prob. 21ECh. 3.1 - Prob. 22ECh. 3.1 - Prob. 23ECh. 3.1 - Prob. 24ECh. 3.1 - Prob. 25ECh. 3.1 - Prob. 26ECh. 3.1 - Prob. 27ECh. 3.1 - Prob. 28ECh. 3.1 - Prob. 29ECh. 3.1 - Prob. 30ECh. 3.1 - Prob. 31ECh. 3.1 - Prob. 32ECh. 3.1 - Prob. 33ECh. 3.1 - Prob. 34ECh. 3.2 - Prob. 1.3CYUCh. 3.2 - Prob. 1.4CYUCh. 3.2 - Prob. 2.1CYUCh. 3.2 - Prob. 3.1CYUCh. 3.2 - Prob. 3.2CYUCh. 3.2 - Prob. 3.3CYUCh. 3.2 - Prob. 4.1CYUCh. 3.2 - Prob. 4.2CYUCh. 3.2 - Prob. 5.1CYUCh. 3.2 - Prob. 5.2CYUCh. 3.2 - Prob. 35ECh. 3.2 - Prob. 36ECh. 3.2 - Prob. 37ECh. 3.2 - Prob. 38ECh. 3.2 - Prob. 39ECh. 3.2 - Prob. 40ECh. 3.2 - Prob. 41ECh. 3.2 - Prob. 42ECh. 3.2 - Prob. 43ECh. 3.2 - Prob. 44ECh. 3.2 - Prob. 45ECh. 3.2 - Prob. 46ECh. 3.2 - Prob. 47ECh. 3.2 - Prob. 48ECh. 3.2 - Prob. 49ECh. 3.2 - Prob. 50ECh. 3.2 - Prob. 51ECh. 3.2 - Prob. 52ECh. 3.2 - Prob. 53ECh. 3.2 - Prob. 54ECh. 3.2 - Prob. 55ECh. 3.2 - Prob. 56ECh. 3.2 - Prob. 57ECh. 3.2 - Prob. 58ECh. 3.2 - Prob. 59ECh. 3.2 - Prob. 60ECh. 3.2 - Prob. 61ECh. 3.2 - Prob. 62ECh. 3.2 - Prob. 63ECh. 3.2 - Prob. 64ECh. 3.2 - Prob. 65ECh. 3.2 - Prob. 66ECh. 3.2 - Prob. 67ECh. 3.2 - Prob. 68ECh. 3.2 - Prob. 69ECh. 3.2 - Prob. 70ECh. 3.2 - Prob. 71ECh. 3.2 - Prob. 72ECh. 3.2 - Prob. 73ECh. 3.2 - Prob. 74ECh. 3.2 - Prob. 75ECh. 3.2 - Prob. 76ECh. 3.2 - Prob. 77ECh. 3.2 - Prob. 78ECh. 3.2 - Prob. 79ECh. 3.2 - Prob. 80ECh. 3.2 - Prob. 81ECh. 3 - Prob. 1CRECh. 3 - Prob. 2CRECh. 3 - Prob. 3CRECh. 3 - Prob. 4CRECh. 3 - Prob. 5CRECh. 3 - Prob. 6CRECh. 3 - Prob. 7CRECh. 3 - Prob. 1PTCh. 3 - Prob. 2PTCh. 3 - Prob. 3PTCh. 3 - Prob. 4PTCh. 3 - Prob. 5PTCh. 3 - Prob. 6PTCh. 3 - Prob. 7PTCh. 3 - Prob. 8PTCh. 3 - Prob. 9PTCh. 3 - Prob. 10PTCh. 3 - Prob. 11PTCh. 3 - Prob. 12PTCh. 3 - Prob. 13PT
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